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larisa [96]
3 years ago
10

team has a 75% chance to win each of the 3 games they will play this week. Clare simulates the week of games by putting 4 pieces

of paper in a bag, 3 labeled "win" and 1 labeled "lose." She draws a paper, writes down the result, then replaces the paper and repeats the process two more times. Clare gets the result: win, win, lose. What can Clare do to estimate the probability the team will win at least 2 games? Explain.
Mathematics
1 answer:
kaheart [24]3 years ago
6 0

Answer: 88

Step-by-step explanation:

check google if its wrong :)

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\frac{x-3}{2x-3}. hole or removable discontinuity at x=2

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Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

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(x-2)(x-3)

Ok now let's factor the second equation:

2x^2-7x+6

Multiply a and c

AC = 12

List factors of 12:

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Factors that add up to -7 and multiply to 12:

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Rewrite equation:

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Group terms:

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Factor out GCF:

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Now let's write out the equation using these factors:

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Here we can factor out the x-2 and the simplified form is:

\frac{x-3}{2x-3}

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

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