Question

The center of a circle is at (0, 0), and the radius of the circle is 3(sqrt)2

Answer 1

Answer:

B

Step-by-step explanation:

The equation of a circle is denoted by: $(x-h)^2+(y-k)^2=r^2$, where (h, k) is the center and r is the radius.

Here, we see that the center is (0, 0), so h = 0 and k = 0. Also, the radius is $3\sqrt{2}$, so r = $3\sqrt{2}$ and $r^2=(3\sqrt{2})^2=9*2=18$.

Then we can write our equation:

$(x-0)^2+(y-0)^2=18$

$x^2+y^2=18$

The answer is B.

Hope this helps!