Answer:
Your answer is 12 and -6
Step-by-step explanation:
12 X -6= -72
12 + -6= 6
9514 1404 393
Answer:
1) c, f
2) a, e
3) b, d
Step-by-step explanation:
If you think about the units associated with a coordinate (feet, for example), then you may recognize the following
a) each difference is of "feet", so each difference will have units of "feet". The ratio of "feet" to "feet" cancels the units, leaving a pure number. In this case, it is called "steepness" in selection e. Steepness is given by the slope formula (2).
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b) The difference in parentheses has units of "feet" (as in (a)), so the square will be "square feet". The sum of two of those will still be "square feet" and the square root of that will be "feet". The units of the formula are those of distance, or length, matching selection d. Distance is given by the distance formula (3).
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c) The form shown is an ordered pair. That is the same as the representation of a coordinate point, selection f. Coordinates of a point are given by the midpoint formula (1).
Answer:
The answer is "between 0.10 and 0.05".
Step-by-step explanation:
For sample 1:
For sample 2:
Calculating the null and alternative hypotheses:
Calculating the test statistic:
Calculating the conservative degrees of freedom:
by using Excel the p-value for left tailed test and for test statistic will be 
with 
.
Answer:
see the attached table
Step-by-step explanation:
We assume the formula of interest is ...
residual = (initial amount)(1 -k)^t . . . . . . assuming k is a positive number
Where T is the half-life, this formula can also be expressed as ...
residual = (initial amount)(1/2)^(t/T)
Then the relationship between k and T is ...
(1 -k)^t = (1/2)^(t/T)
or ...
1 -k = (1/2)^(1/T)
This lets us write k in terms of T as ...
k = 1 -(1/2)^(1/T)
and it lets us write T in terms of k as ...
log(1-k) = (1/T)log(1/2)
T = log(1/2)/log(1-k)
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The attached spreadsheet table implements these formulas to compute T from k and vice versa. Formatting is in % and to four decimal places as required by the problem statement.
Answer: 1 minute 33 seconds
Step-by-step explanation:
Theo is practicing for a 5 km race which he usually runs for a normal time of 25 minutes and 19 seconds
but yesterday, he ran for only 23 minutes and 43 seconds.
From the above information,
Normal time = 25 minutes and 19 seconds.
Yesterday's time= 23 minutes and 43 seconds
To know how much faster Theo ran, we find the difference between the normal time and yesterday's time which is.
25 minutes 19 seconds - 23 minutes 43 seconds
25 minutes 19 seconds
- 23 minutes 43 seconds
= 1 minute 36 seconds.
He ran 1 minute 33 seconds faster.
