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3 years ago

WILL GIVE BRAINLIEST!!!!!!! Kate has 4 feet of rope. She cuts the rope into pieces that are each

Mathematics

1 answer:

Delvig [45]3 years ago

5 0

<h2>Answer:</h2>

<h2>Step-by-step explanation:</h2>

4 1/5 ÷ 3/5 = 7

Kate cut 7 pieces of rope.

<h2>#BrainliestAnswer</h2><h2>#CarryOnLearning</h2>

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Cate solved an inequality to find c, the possible number of cats that a shelter can house. She found that c < 28. Which state

ASHA 777 [7]

Answer:

The shelter can house 17 cats because

17 < 28.

Step-by-step explanation:

We cannot have fractions of cats, and we cannot have a negative number of cats. So the third statement is reasonable because c < 28.

8 0

2 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago

How much do a dozen cookies weigh?

yaroslaw [1]

0.43 oz

Hope this helps...

7 0

3 years ago

Read 2 more answers

Pls need help!!!! Giving brainliest to the person that gives me the right awnser

jeka57 [31]

Answer:

you only have the answer choices not the question itself

could you please attach the question so i can help?

6 0

3 years ago

I need some serious help on this

motikmotik

BB BA BB BA
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4 0

3 years ago