Gcf and lcm of 6 and 9

Paha777 [63]

Plug in each pair into each system of inequalities. And see which one fits

4 0

3 years ago

Antonio is a biologist studying life in a pond. He needs to know how deep the water is. He notices a water lily sticking straigh

quester [9]

For this problem we can represent the situation as a rectangle triangle.
x: depth of water.
40: Base. "Antonio pulls the lily to one side, keeping the stem straight, until the blossom touches the water at a spot"
x + 8: Hypotenuse. "He notices water lily sticking straight up from the water, whose blossom is 8 cm above the water's surface." Antonio pulls the lily to one side, keeping the stem straight, until the blossom touches the water at a spot".
By the Pythagorean theorem we have:
x ^ 2 + 40 ^ 2 = (x + 8) ^ 2
Clearing x:
x ^ 2 + 1600 = x ^ 2 + 16x + 64
x ^ 2 - x ^ 2 = 16x + 64 - 1600
0 = 16x -1536
1536 = 16x
1536/16 = x
x = 96
answer:
1) x ^ 2 + 40 ^ 2 = (x + 8) ^ 2
2) the depth of the water is
x = 96

6 0

2 years ago

Explain how to model the division of -20 by -5 on a number line.

Elina [12.6K]

So you label -20 on the number line. Then you split it into -5 and count much space is in between the <em>'split'.</em>

4 0

2 years ago

Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia

Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$