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2 years ago

A watch lost 1 minute 18 seconds in 39 days. How many seconds did it lose per day?

1 answer:

6 0

ATO,
We should convert 1.18 minutes into seconds
1 minute = 60 seconds
60 + 18 seconds = 78 seconds
We should divide with the days
So,
78 seconds ÷ 39 days = 2 seconds per day.

So,it lose 2 seconds per day.

Please mark mine answer as Brainliest
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Please help me with the question

Alenkasestr [34]

3•y+2
3 and y are being multiplied and then you add the two!:)

3 0

2 years ago

Profit is the amount of money that remains after all expenses of a project have been paid. The year has just ended, and Ajax C

lilavasa [31]

Answer:

the Profit earned by the company is $280,489

Step-by-step explanation:

Total Cost of 5 projects awarded = $7,435,000

Cost of Project 1 = $1,245,000

Cost of Project 2 = $985,689

Cost of Project 3 = $1,723,000

Cost of Project 4 = $2,567,054

Cost of Project 5 = $633,768

We need to find the profit earned by the company.

First we need to find Total cost spent on all 5 projects.

It can be found by adding cost spent on all projects.

Total cost spent on all 5 projects = Cost of Project 1 + Cost of Project 2 + Cost of Project 3 + Cost of Project 4 + Cost of Project 5

Total cost spent on all 5 projects = $1,245,000+ $985,689 + $1,723,000+ $2,567,054 + $633,768

Total cost spent on all 5 projects = $7,154,511

Now we can calculate profit earned using formula:

Profit earned = Total Cost of 5 projects awarded - Total cost spent on all 5 projects

Profit earned = $7,435,000 - $7,154,511

Profit earned = $1,280,489

So, the Profit earned by the company is $280,489

6 0

3 years ago

27x 5 + 9x 4 - 18x 3) 9x 2

notka56 [123]

In guessing it's 2,106.......

4 0

3 years ago

For an angle θ, tan(θ) is a negative number. Which quadrants might θ be in?

Klio2033 [76]

So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.

4 0

2 years ago

Read 2 more answers

5x – (13 – x) >_9x – 7

ad-work [718]

Answer:

x<_2

Step-by-step explanation:

first off solve this like a regular equation the >_ dosent matter till later

so basically first multiply - by 13 and -x so you get -13 and x (multiplying two negatives = a positive)

so its 5x-13+x>_9x-7

add 5x and x to get 6x-13 on one side

then you get 6x-13>_9x-7 then subtract -9x from both sides

so its now -3x-13>_-7 add 13 so you get -3x>_6

then divide both sides by -3 (when you divide an equation with a >< or <_ >_ by a negative number that sign switches) so it will now be x<_2

that your final answer hope this helps :)

6 0

3 years ago