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2 years ago

8

How many times does 12 go into 62.

2 answers:

Aleks04 [339]2 years ago

4 0

5 whole with the denominater of 12 and the numerater of 2

pentagon [3]2 years ago

3 0

12 can go into 62, 5 times

We will have a remainder of 2

Therefore, our final answer is that 12 can go into 62 five times. And their will be a remainder of 2.

A word problem to represent this:- James had 62 apples, he wanted to give 12 friends apples. How much apples will each get and how much will be left for james. (He wants to give everyone a fair amount)

We have our equation: 12x=62

12x=62
12/12= 62/12
x=5 and remainder of 2

So each of James friends get 5 apples and James gets 2 for himself.

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Sam is filling up his pool. The water hose filled the 392 gallon pool in 49 minutes. At what rate did the hose fill the pool in

cestrela7 [59]

Your answer would be 8 Hammond per minute. Hope this helps!

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2 years ago

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Solve. 3t < –15 (1 point)<br> t < –5<br> t > –5<br> t < –45<br> t > –45

Kipish [7]

I hope this helps you

3t÷3 < -15÷3

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3 years ago

Plz help, I need help!!!!

Otrada [13]

Answer:

56 multiplied by 9 = 504

Step-by-step explanation:

55.8 rounded is 56, and 9.12 rounded is 9

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2 years ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

<u>Step 1: Define</u>

$f(x) = \frac{1}{\sqrt{800-2x} }$

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

$u = 800-2x\\du = -2dx$

<u>Step 3: Integrate</u>

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0

3 years ago

Find the midpoint of line segment HX with coordinates H(-1,3) and X (7, -1).

viva [34]

Answer:

OK midpoint is actually really easy I got u

Step-by-step explanation:

X2+X1 divided by 2

Y2+Y1 divided by 2

7+-1/2 is 6.5

-1+3/2 is 0.5

(6.5,0.5)

5 0

2 years ago