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3 years ago

Identify the oblique asymptote of f(x) = 2x^2+3x+8/x+3

Mathematics

2 answers:

Lostsunrise [7]3 years ago

7 0

Answer:

Step-by-step explanation:

7vito6u

Aloiza [94]3 years ago

6 0

Answer:

Find the oblique asymptote using long polynomial division.

Vertical Asymptotes:

x = − 3

No Horizontal Asymptotes

Oblique Asymptotes:

y = 2 x ^2 + 3 x

Step-by-step explanation:

Hope this helps! :)

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A standard deck of cards contains 52 cards. One card is selected from the deck. Compute the probability of randomly selecting a

lisabon 2012 [21]

P(selecting a 10)= 4/52
P(selecting a 2)= 4/52
P(selecting a 4)=4/52
P(selecting an Ace)=4/52
P(selecting a diamond)=13/52

3 0

3 years ago

Write the following in vertical columns. Then subtract.<br><br>b) 4a - 7c from 4a - 3b + 8c<br>

andreyandreev [35.5K]

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴ Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

6 0

3 years ago

H(x) = 2^x<br>Solve the equation h^-1 (x) =0.5

Ludmilka [50]

Answer:

The answer is

Step-by-step explanation:

To solve the equation we must first find h-¹(x)

To find h-¹(x) equate h(x) to y

That's

<u>Next interchange the terms </u>

x becomes y and y becomes x

That's

<u>Make y the subject</u>

Take logarithm to base 2 to both sides

That's

But

So we have

Now we can solve the equation

We have

Convert the logarithm into exponential form using the fact that

So we have

But

So we have the final answer as

Hope this helps you

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3 years ago

How do i find the y-intercept for f(x)=|x|-5

wel

The y-intercept for f(x)=|x|-5 is (-5). Just look at the function as slope-intercept form and find the number that is not being multiplied by x. That number will usually be your y-intercept.

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3 years ago

Read 2 more answers

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Lena [83]

Answer:

I think B but I am not sure.

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3 years ago