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KiRa [710]
4 years ago
12

Another question: Brainliest if someone can match the correct answers to the correct working out. MATHS HELP URGENT PLZZZ

Mathematics
1 answer:
natita [175]4 years ago
5 0

The correct answer is F, C, G, B.

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Luci cuts a board that is 3/7 yard long into pieces that are 3/14 yard long. How many pieces does she cut?
andreyandreev [35.5K]
Luci cuts 2 pieces because 3/7×2=3/14
6 0
3 years ago
Which is the correct label for the angle?<br> A<br> С<br> B<br> O ZA<br> ZBCA<br> OZb<br> O ZCBA
elixir [45]

Step-by-step explanation:

option d is correct

Angel CBA

<em>hope </em><em>this</em><em> answer</em><em> helps</em><em> you</em><em> dear</em><em>.</em><em>.</em><em>take </em><em>care </em><em>and </em><em>may</em><em> u</em><em> have</em><em> a</em><em> great</em><em> day</em><em> ahead</em><em>!</em>

5 0
3 years ago
a colleague needs to move a 500 pound object that's on a lever. the fulcrum is 6 inches from the object. If your colleague weigh
Dafna11 [192]

Answer:

Step-by-step explanation:

The easier way to figure this is by using the concept of torque in physics. If the torque of the man is greater than that experienced by the box, the lever will tilt in the man's favor (in other words, he will move down and the box will be lifted). Torque is found by multiplying the perpendicular force by the length of the lever arm. Because we want the man's torque to be greater than the box's torque, the inequality is:

\tau_{man}>\tau_{box} and

180r>500(.1524) That decimal is 6 inches in terms of meters.

180r > 76.2 so

r > .42 meters or `16.67 inches. The man has to sit at a distance greater than 16.67 inches in order for the box to be lifted by the lever.

6 0
3 years ago
50+51+52+...+101=...<br>Can you help me? I do not understand
Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

But S=S^*, as we pointed out, so

2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926

5 0
3 years ago
4. a. On the grid, draw at least three different quadrilaterals that can each be
Julli [10]

Answer:

this is just for part A sorry i dont get part B

oof bad drawing of a trapezoid

4 0
4 years ago
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