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3 years ago

Answer qn in attachment

Mathematics

1 answer:

leva [86]3 years ago

4 0

Answer:

$\implies \dfrac{ -4x+7}{2(x-2) }$

Step-by-step explanation:

The given expression to us is ,

$\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}$

Now take the LCM as ( x - 1 ) and Simplify , we have ,

$\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}$

Simplifying further , we get ,

$\implies \dfrac{ -4x+7}{2(x-2) }$

Hence the second option is correct .

You might be interested in

At the Canada Open Tennis Championship, a statistician keeps track of every serve that a player hits during the tournament. The

kondaur [170]

Answer:

a) 54 mph to 144 mph

Step-by-step explanation:

We don't know the shape of the distribution, so we use Chebyshev's Theorem to solve this question. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

At least eight-ninths of the player's serves.

8/9 is approximately 89%

Mean: 99, standard deviation: 15

99 - 3*15 = 54

99 + 3*15 = 144

So the correct answer is:

a) 54 mph to 144 mph

8 0

3 years ago

Identify Arithmetic Mean, Geometric Mean and Harmonic Mean from the following averages: 56.4, 59.8 and 55.8

photoshop1234 [79]

If you would like to calculate the arithmetic mean, geometric mean, and harmonic mean from the following averages, you can calculate this using the following steps:

averages: 56.4, 59.8, 55.8
the number of values: 3

arithmetic mean:
(56.4 + 59.8 + 55.8) / 3 = 57.33

geometric mean:
(56.4 * 59.8 * 55.8)^(1/3) = 57.31

harmonic mean:
3 / (1/56.4 + 1/59.8 + 1/55.8) = 57.28

7 0

3 years ago

The difference of twice a number and 2 is at least −26.

natita [175]

$2x - 2 \geqslant - 26$

8 0

3 years ago

Read 2 more answers

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago

Write the product of -2 and (3 - 5a) as the sum of two factors

NARA [144]

-6 + 10a

-2x3=6 and -2x-5a is 10a

7 0

3 years ago

Answer qn in attachment​

Answer qn in attachment