P+3/m=-1 solve for p

Can someone help me please !! I’m so confused Thank you

sergiy2304 [10]

Answer:

I have no idea if this would be right but I am guessing (for the 1/5 one) if you put 5 different colored marbles in a container and wanted to pull out a red one. You can also do this for the 1/10 one just use a different object.

5 0

3 years ago

A students home is 3.25 miles from school. A soda shop is located 900 feet farther down the road from school. What is the total

notka56 [123]

1 mile = 5,280 feet.

Convert the 0.25 mile to feet:

0.25 miles = 0.25 x 5,280 = 1,320 feet.

Add the soda shop distance to this:

1,320 + 900 = 2,220 feet.

Total distance is 3 miles and 2,220 feet

5 0

3 years ago

Question:

aivan3 [116]

Answer:

part A) The scale factor of the sides (small to large) is 1/2

part B) Te ratio of the areas (small to large) is 1/4

part C) see the explanation

Step-by-step explanation:

Part A) Determine the scale factor of the sides (small to large).

we know that

The dilation is a non rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional

so

Let

z ----> the scale factor

$\frac{CB}{C'B'}=\frac{CD}{C'D'}=\frac{BD}{B'D'}$

The scale factor is equal to

$z=\frac{CB}{C'B'}$

substitute

$z=\frac{4}{8}$

simplify

$z=\frac{1}{2}$

Part B) What is the ratio of the areas (small to large)?

<em>Area of the small triangle</em>

$A=\frac{1}{2}(2)(4)=4\ units^2$

<em>Area of the large triangle</em>

$A=\frac{1}{2}(4)(8)=16\ units^2$

ratio of the areas (small to large)

$ratio=\frac{4}{16}=\frac{1}{4}$

Part C) Write a generalization about the ratio of the sides and the ratio of the areas of similar figures

In similar figures the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In similar figures the ratio of its areas is equal to the scale factor squared

4 0

3 years ago

How do you solve 5x +x

34kurt

If you are just simplifying it it would be 6x because it's 5x plus one more x but if you are trying to find x then I have no idea

4 0

3 years ago

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Why is -16 the leading coefficient in quadratic applications

Lady bird [3.3K]

Answer:

Step-by-step explanation:e equation has a leading coefficient of 1 or if the equation is a difference of squares. The zero-factor property is then used to find solutions. ... Another method for solving quadratics is the square root property. The variable is squared.

3 0

3 years ago

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