First, do 40 - 12 = 28 (Subtract the change), then do 28 / 7 to get 4, so then we do the cans times 3 to see how many individual balls he has, which would be 12
Answer:
16 2/3 %
Step-by-step explanation:
Since the price went down, we are find the percent decrease.
Percent decrease = (original price - new price)/ original price
= (90 - 75)/90
=15/90
.1666666666666
Changing to percent form
16.6666666666666666666666%
16 2/3 %
Answer: The price for the computer = $1152
Step-by-step explanation:
Let the first boy = F
Let the second boy = S
Let the price of computer = C
The second boy had 5/ 6 of the money the first had. I.e
S = 5/6 F
Then F = 6/5S ......(1)
The first boy had 7 /8 of the price of the computer. That is
F = 7/8C ....... (2)
Substitute F in (1) into (2)
6/5S = 7/8C
S = 5/6 × 7/8C
S = 35/48C ......(3)
Together they had $696.00 more than they need to pay. That is
F + S = C + 696 ........ (4)
Substitute equation 2 and 3 into 4
7/8C + 35/48C = C + 696
0.875C + 0.729C = C + 696
0.604C = 696
C = 696/0.604
C = 1152 dollars
Therefore, the price for the computer = $1152
1: 30%
2: 50%
3: 2%
4: 33. 3%
5: 80% chance of thunderstorm
6: 60% of not selecting red
Answer:
Option D. ![\sqrt[4]{\frac{3x^{2}}{2y}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B2y%7D%7D)
Step-by-step explanation:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D)
![\sqrt[4]{(\frac{24}{128})\times (\frac{x^{6}}{x^{4}})\times (\frac{y}{y^{5}})}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B24%7D%7B128%7D%29%5Ctimes%20%28%5Cfrac%7Bx%5E%7B6%7D%7D%7Bx%5E%7B4%7D%7D%29%5Ctimes%20%28%5Cfrac%7By%7D%7By%5E%7B5%7D%7D%29%7D)
= ![\sqrt[4]{(\frac{3}{16})\times {(x)^{6-4}}\times{(y)^{1-5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B3%7D%7B16%7D%29%5Ctimes%20%7B%28x%29%5E%7B6-4%7D%7D%5Ctimes%7B%28y%29%5E%7B1-5%7D%7D%7D)
= ![\sqrt[4]{(\frac{3}{16})\times x^{2}y^{-4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B3%7D%7B16%7D%29%5Ctimes%20x%5E%7B2%7Dy%5E%7B-4%7D%7D)
= ![\sqrt[4]{\frac{3}{(2)^{4}}\times x\times y^{-4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3%7D%7B%282%29%5E%7B4%7D%7D%5Ctimes%20x%5Ctimes%20y%5E%7B-4%7D%7D)
= ![\sqrt[4]{(3\times x^{2)\times (\frac{y^{-1}}{2})^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%283%5Ctimes%20x%5E%7B2%29%5Ctimes%20%28%5Cfrac%7By%5E%7B-1%7D%7D%7B2%7D%29%5E%7B4%7D%7D%7D)
= ![\frac{y^{-1}}{2}\sqrt[4]{3x^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7By%5E%7B-1%7D%7D%7B2%7D%5Csqrt%5B4%5D%7B3x%5E%7B2%7D%7D)
=
Option D. is the correct answer.
