1. Using the exponent rule (a^b)·(a^c) = a^(b+c) ...

Simplify. Write in Scientific Notation
2. You know that 256 = 2.56·100 = 2.56·10². After that, we use the same rule for exponents as above.

3. The distributive property is useful for this.
(3x – 1)(5x + 4) = (3x)(5x + 4) – 1(5x + 4)
... = 15x² +12x – 5x –4
... = 15x² +7x -4
4. Look for factors of 8·(-3) = -24 that add to give 2, the x-coefficient.
-24 = -1×24 = -2×12 = -3×8 = -4×6
The last pair of factors adds to give 2. Now we can write
... (8x -4)(8x +6)/8 . . . . . where each of the instances of 8 is an instance of the coefficient of x² in the original expression. Factoring 4 from the first factor and 2 from the second factor gives
... (2x -1)(4x +3) . . . . . the factorization you require
Answer:
22x+138
Step-by-step explanation:
just add 11x+11x+9+9+60+60
Answer:
1.6 hours
Step-by-step explanation:
The computation of the number of hours is shown below:
For water sports
= 20x + 8
And,For splash of fun
= 25x
Now the cost of both would be same
i.e.
20x + 8 = 25x
8 = 5x
x = 1.6 hours
Answer: Angle bisectors
Step-by-step explanation:
The incenter is the point forming the origin of a circle inscribed inside the triangle. Like the centroid, the incenter is always inside the triangle. It is constructed by taking the intersection of the angle bisectors of the three vertices of the triangle.
Answer:
0.333
Step-by-step explanation:
The first sequence starts at 1 and has a common difference of 2. It will include every odd number in the range.
__
The second sequence starts at 1 and has a common difference of 3. It will include odd numbers and the even numbers 4, 10, 16, .... That is, all even numbers of the form 6n -2 will be included. The last one corresponds to the largest value of n such that ...
6n -2 ≤ 1000
6n ≤ 1002
n ≤ 167
That is, 167 even numbers will also be excluded.
__
The third sequence starts at 1 and has a common difference of 4. Every number in this sequence is also a number in the first sequence.
__
So the numbers in these sequences include all 500 odd numbers and 167 even numbers, for a total of 667 numbers. The probability that a randomly chosen number is not in one of these sequences is ...
(1000 -667)/(1000) = 333/1000 = 0.333 . . . . p(not a sequence term)