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iogann1982 [59]
3 years ago
9

Using a compass and straight edge, construct a tangent line to a circle from a given exterior point. Evidence of your constructi

on must be shown to earn credit.

Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0
In the figure attached, red circle A and red point B are the circle and external point of interest. Note that we must know where the center of circle A is. If we don't know that, there are construction techniques for finding it, but that is beyond the scope of this answer.

Step 1. Set your compass to a radius greater than half the length of segment AB. Here, we have made the radius AD.

Step 2. Draw arcs above and below the center of segment AB centered at A and B using the radius of Step 1. Here the "arc" is shown a a full (green) circle. Only the points where the arcs intersect (E and F) are of interest, so it is not necessary to draw the full circle.

Step 3. Identify the points of interesection (E and F) of the arcs of Step 2, then draw a line segment between them. This segment (EF) is the perpendicular bisector of AB. Mark point G where it intersects segment AB. As with the green circles, it is not necessary to draw the whole line EF, since we are only interested in the location of the midpoint of AB, which is point G.

Step 4. Using G as the center, and GA or GB as the radius, draw semicircle AHB. The point of intersection H is the only part of that (blue) circle of interest, so it is not necessary to draw the whole thing.

Step 5. Finish the consruction by drawing tangent line BH.

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valina [46]
Let's start with day 1:

We know that Joe practiced from 6:30 to 7:05
An hour is 60 minutes
Joe practiced for the 30 minutes left in that hour and 5 minutes into the next

30+5=35

So, he was playing for 35 minutes on the first day

Now, we can do the same thing for the second day:

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Now we want to add the number of minutes he practiced for both days

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6 0
3 years ago
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use the diagram to find the distance across the suspension bridge. Round your answer to the nearest foot
3241004551 [841]

Applying the tangent ratio, the distance across the suspension bridge is: 499.2 ft.

<h3>What is the Tangent Ratio?</h3>

Where we are given a right triangle, the tangent ratio is determined using the formula, tan ∅ = opposite side/adjacent side.

The diagram atatched beow whos the distance across the suspension bridge which consists of 6 identical right triangles.

Find the adjacent side of each right triangle using the tangent ratio:

∅ = 32

Opposite side = 52 ft

Adjacent side = x

Plug in the values into the tangent ratio:

tan 32 = 52/x

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x = 83.2 ft.

Distance across the suspension bridge = 6(83.2) = 499.2 ft.

Therefore, applying the tangent ratio, the distance across the suspension bridge is: 499.2 ft.

Learn more about the tangent ratio on:

brainly.com/question/4326804

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2 years ago
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erik [133]
Down 3 over 1
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Can anyone check this if it’s right.
Romashka [77]

Yes this is the right answer

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3 years ago
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