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Mademuasel [1]
3 years ago
8

When the exponential phase of a logistic growth curve of the population ceases

Biology
1 answer:
algol [13]3 years ago
6 0
<span>C. population growth begins to slow down</span>
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Darwin called the ability of an organism to survive and reproduce in its enviorment
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Darwin called the ability of an organism to survive and reproduce in its environment fitness.
Some organisms were fit to do all of these things, whereas others were not. 
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Where do hydrogen ions come from
Sedaia [141]

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Fossil fuels specifically natural gas

Explanation:

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What is the probability of a homozygous recessive individual (ss) producing a gamete with a dominant allel (S)?
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The probability that a homozygous recessive individual would be producing a dominant allele would be 0%. If expressed as a percentage, this is because the individual does not even have the possible allele in its genotype for whatever trait or feature that the protein codes for.
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Prokaryotes, like most living organisms, need movement to locate food and to survive.
zmey [24]

Answer:

Explanation:

Prokaryotes, like most living organisms, need movement to locate food and to survive. If a prokaryote needed to move to a new food source, which structure would it use for locomotion?

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3 years ago
A woman and a man are both heterozygous for a recessive allele for a rare genetic disease. If they have one child, what is the p
makkiz [27]

Answer:

  • If they have one child, the probability that he or she will be affected is 1/4.
  • If they have two children, the probability that at least one of them will be affected is 7/16.

Explanation:

A cross between two heterozygous Aa individuals will produce the followinf offspring: 1/4 AA, 2/4 Aa and 1/4 aa.

Since the disease is recessive, 1/4 of the offspring will have the <em>aa </em>genotype and 3/4 of the offspring will be unaffected.

Every time they have children new gametes were generated <u>independently</u>.

The probability of having <u>no</u> affected children both times is, according to rules of probability for independent events, 3/4 × 3/4 = 9/16 (it's the probability of having a healthy child the first time multiplied by the probability of having a healthy child the second time).

The probability of having at least one affected child is 1 - probability of no affected children = 1 - 9/16 = 7/16.

8 0
3 years ago
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