Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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Answer:
D
Step-by-step explanation:
(7 × 10-7) × 0.06
7 × 0.06 × 10^-7
0.42 × 10^-7
4.2 × 10^-8
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Answer:
(x-5) (x+1)
Step-by-step explanation:
x^2 - 4x - 5
Factor
What 2 numbers multiply to -5 and add to -4
-5*1 = -5
-5+1 = -4
(x-5) (x+1)
