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hodyreva [135]
3 years ago
13

{ PLEASE ANSWER QUICKLY, PROBLEM DUE ASAP } The functions f(x) and g(x) are defined below. Which expression is equal to f(x) + g

(x)?

Mathematics
1 answer:
8090 [49]3 years ago
7 0

Answer:

Option C. 2x + 20 / x² + 6x – 40

Step-by-step explanation:

f(x) = x + 16 / x² + 6x – 40

g(x) = 1 / x + 10

To find f(x) + g(x), please refer to the attached photo.

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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Solve ( x - 2)( x + 7) =0
lara31 [8.8K]

Answer:

x = 2 or

x = -7

Step-by-step explanation:

(x - 2)(x + 7) = 0

x - 2 = 0

Add 2 to both sides

x - 2 + 2 = 2 + 0

x = 2

OR

x + 7 = 0

Subtract 7 from both sides

x + 7 - 7 = 0-7

x = -7

Therefore

x = 2 or

x = -7

6 0
3 years ago
2. What is the value of the expression?
polet [3.4K]

Answer:

B. 8.35

Step-by-step explanation:

3.5 x 1.7 = 5.95

5.95 + 2.4 = 8.35

You multiply first because of PEMDAS.

P=parenthesis

E=exponents

M=multiply
D=divide
A=add
S=subtract

4 0
1 year ago
Read 2 more answers
Hey! Please help me
mafiozo [28]

Answer:

Exact: 10.08

To 1 decimal place: 10.1

Step-by-step explanation:

Just ask.

Hope this helps.

3 0
2 years ago
How can you write 23/3 as a mixed number?
Illusion [34]
23/3 = 7 2/3 <======
3 0
2 years ago
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