Answer:
First car: 30 gallons
Second car: 35 gallons
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations:
Total gas consumption was 65:
x+y=65
Where:
x = gallons consumed by the first car
y = gallons consumed by the second car
The first car has a fuel efficiency of 20 miles per gallon of gas and the second has a fuel efficiency of 30 miles per gallon of gas, the two cars went a combined total of 1650 miles:
x 20+y 30 = 1650
The system is:
x+y=65 (1)
x 20+y 30 = 1650 (2)
Isolating y on (1)
y = 65-x
Replacing y= 65-x on (2):
x 20+(65-x)30 = 1650
20x +1,950-30x= 1650
20x-30x= 1650-1950
-10x= -300
x= -300/-10
x = 30 gallons
Back to (1)
y =65-x
y =65-30
y= 35 gallons
Feel free to ask for more if needed or if you did not understand something.
Answer:
40 + 4.5v ≥ 145
Step-by-step explanation:
Substitute 1 for x in each of your equations.
f(x)=7-3x
which is
f(1)=7-3(1)
=3
Do the same for g(x)
g(x)=3x-7
which is
g(1)=3(1)-7
=-4
Then subtract g(x) from f(x):
3-(-4)
=7
:)
<span>Which ratio is equivalent to 21:56
</span>
Answer: 3:8
If price of laptop=x
Let number of months required to save the necessary amount be y
5*2^y=x
2^y=x/5
y=log2 x/5
