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3 years ago

Need help with both of them !

Mathematics

1 answer:

vovangra [49]3 years ago

6 0

After calculating for ten minutes, I got 1. B and 2. D

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Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appea

makkiz [27]

Answer:

0.2

Step-by-step explanation:

If two number cubes as tossed then the total possible out comes are

Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

Number of elements in sample space are

n(S)=36

Let A and B represent the following events.

A = The sum will be 4.

A = {(1,3),(2,2),(3,1)}

n(A) = 3

B = The sum is less than or equal to 6.

B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

n(B)=15

Intersection of both events is

A∩B = {(1,3),(2,2),(3,1)}

n(A∩B) = 3

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{36}$

$P(B)=\dfrac{n(B)}{n(S)}=\dfrac{15}{36}$

$P(A\cap B)=\dfrac{n(A\cap B)}{n(S)}=\dfrac{3}{36}$

We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.

$P(\frac{A}{B})=\dfrac{P(A\cap B)}{P(B)}$

$P(\frac{A}{B})=\dfrac{\frac{3}{36}}{\frac{15}{36}}$

$P(\frac{A}{B})=\dfrac{3}{15}$

$P(\frac{A}{B})=\dfrac{1}{5}$

$P(\frac{A}{B})=0.2$

Therefore, the required probability is 0.2.

3 0

3 years ago

May i get help with 5-9 questions pls

Zepler [3.9K]

Answer:

5) r=40 gals/min

6) r= 125 mm/hr

7) $2600

8) d = 36 in

9) h= 1176 m

Step-by-step explanation:

5) r=v/r

r= 15,600 gals ÷ 390 mins

r= 40 gals/min

6) r=v/t

r= 1000mm ÷ 8 hrs

r= 125 mm/hr

7) $4500 - $1900 = $2600

8) C = Pi x d

c/Pi =d

113 in/3.14 = d

d = 36 in

9) Formula for h

h = 2 x a/b

h = 2 (84m2/12m)

h = 2 (7056/12)

h = 2(588)

h = 1176 m

4 0

3 years ago

The cone shown has a diameter of 18 meters and a slant height of 15 meters. Which choice is closest to the lateral surface area?

never [62]

If you unfurl the lateral "face" of a cone, you get the sector of a circle whose central angle subtends an arc with length $L$ equal to the circumference of the cone's base, and a radius equal to the slant height $s$ of the cone.

Since the diameter of the base is 18m, the circumference of the base is about $3.14\times18=56.52$ meters, so this is the value of $L$ .

You're given a slant height of $s=15$ meters.

Now, the following proportional relation holds for any circle:

$\dfrac{\text{area of sector}}{\text{area of circle}}=\dfrac{\text{arc length of sector}}{\text{circumference of circle}}$

This translates to

$\dfrac A{\pi\times s9^2}=\dfrac s{2\pi s\times9}$

(remember, we're talking about a sector of a circle with radius $s$ and arc length $18\pi$ ). Solving for $A$ :

$\dfrac A{81\times3.14}=\dfrac{15}{18\times15\times3.14}$
$A=\dfrac92=4.5$

So the area of the lateral face is approximately 4.5 square meters.

7 0

3 years ago

Read 2 more answers

Write the slope intercept form of the equation. through (4,4) and (-5,4)

victus00 [196]

The answer you are looking for is 0

3 0

3 years ago

Which of the following expressions is written in scientific notation?

attashe74 [19]

Answer:

D 31.4 × 10 4