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Masja [62]
4 years ago
10

choose the equation of the horizontal line that passes through the point (−2, −1). y = −1 y = −2 x = −2 x = −1

Mathematics
2 answers:
NNADVOKAT [17]4 years ago
6 0
For a horizontal line, gradient is zero;
y=mx+c
since m=0
y=c
Replacing for y from given point;
-1=c
c=-1
y-1
Anastaziya [24]4 years ago
3 0

Answer:

y=-1


Step-by-step explanation:

<em>A </em><em>Horizontal Line</em><em> has equation of the form  y=a  where a is the y-coordinate.</em>

The point here given in this problem is  (-2,-1)

<em>What's the y-coordinate? It is -1</em>

So the Horizontal Line equation will be  y=-1

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Step-by-step explanation:

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<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

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<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

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<em>collecting the roots on one side and applying exponent rule</em>

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<em>combining all powers of 2</em>

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