Answer:
4.5 M
Explanation:
70.0 ml was mixed in 3.00 M of Na2SO4
30.0 ml was mixed in 1.00 M of NACL
The first step is to convert 70 ml to liters
= 70/1000
= 0.07 liters
The formular for molarity is
moles/liters
The number of moles in Na2S04 can be calculated as follows
Let y represent the number of moles
3M= y moles/0.07
= 3×0.07
= 0.21 moles
Since Na2So4 has 2 moles of Na then the number of moles is
= 2×0.21
= 0.42 moles
Convert 30ml to liters
= 30/1000
= 0.03 liters
The number of moles in Nacl can be calculated as follows
Let y represent the number of moles
1M= y moles/0.03
= 1×0.03
= 0.03 moles
Since Nacl has 1 mole of Na then the number of moles is
= 1 × 0.03
= 0.03 moles
Therefore the final Na+ can be calculated as follows
Total moles = 0.03 moles + 0.42 moles
= 0.45 moles
Total liters= 0.07 liters + 0.03 liters
= 0.1 liters
Na+ = 0.45/0.1
= 4.5 M
Hence the final Na+ in the solution is 4.5 M
