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jonny [76]
3 years ago
7

colton swam once along the length of a pool that has a perimeter of 124 yd. the width of the pool is 20 yd. how many yards to co

lton swim
Mathematics
2 answers:
Ad libitum [116K]3 years ago
6 0

Answer:

how to have s*x with ur mom at night

Step-by-step explanation:

pychu [463]3 years ago
4 0
If my calculations are correct, Colton swam 288 yards. Really hope this helps.
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3A + 4N - 5A + 3 - 8N + 11 =
Anit [1.1K]

Answer:

-2a-4n+14

Step-by-step explanation:

7 0
3 years ago
1)The original price of concert is $100. They are on sale for 21% off. How much will the tickets cost after the discount? 2)Ms.B
mel-nik [20]
1.  79%  Take 100 x 21%=21, then subtract 21 from 100 = 79
2.  $138  Take 1200 x 11.5%= $138
3 0
3 years ago
Two jets leave an airport at the same time, flying in opposite directions. The first jet is traveling at three hundred seventy-s
gladu [14]
Here is the set using D = rt.


Jet 1:

rate = 377 mph

time = x

Distance = 9128 miles

Jet 2:

rate = 275 mph

time = x

Distance = 9128 miles

Equation:

377x + 275x = 9128

You finish.
8 0
4 years ago
Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3
AlexFokin [52]
The ODE is separable, i.e. you can write

\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx

Integrating both sides gives the general solution.

\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx
y=-\ln|\cos x|+C

Given that y\left(\dfrac\pi4\right)=3, we have

3=-\ln\left|\cos\dfrac\pi4\right|+C
3=-\ln\dfrac1{\sqrt2}+C
3-\ln\sqrt2=C


and so the particular solution to the IVP is

y=-\ln|\cos x|+3-\ln\sqrt2
y=3-\ln|\sqrt2\cos x|
4 0
4 years ago
Jalil and Victoria are each asked to solve the equation ax – c = bx + d for x. Jalil says it is not possible to isolate x becaus
Iteru [2.4K]
<span>solve the equation ax – c = bx + d for x:

1) Group the x terms together on the left:     ax - bx - c = d

2) Group the constant terms together:          ax - bx = c + d

3) factor out x:                                             x(a - b) = c + d

4) Divide both sides of the equation by (a - b) to obtain a formula for x:
                                                       c+d
</span>           x(a - b) = c + d   =>    x = ---------
                                                       a-b

This shows that the given equation CAN be solved for x, but there is a restriction:  a must NOT equal b, because if a-b = 0, we'd have division by zero (which is not defined).

Where is Victoria's solution?  Please share it if you want to discuss this problem further.  Thank you.

8 0
3 years ago
Read 2 more answers
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