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jasenka [17]
3 years ago
8

The work of a student to solve a set of equations is shown:

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0
It might be step 4 where it got dropped by step 3
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Which graph represents the solution set of y = x2 + 4x + 3 and y = 2x + 6?
dybincka [34]
I hope this helps you x^2+4x+3=2x+6 x^2+2x-3 =0 x +3 x -1 (x+3)(x-1)=0 x+3=0 x= -3 x-1=0 x=1
3 0
3 years ago
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What type of endorsement is illustrated by the following example:
Bezzdna [24]
When receiving a check from someone, you'll see that there are lines on the back. Those lines are for the check to be endorsed so you can cash it or deposit your money. Most of the time you'll just sign the back to endorse it and put it in your account or get money in return. However, there are special cases that can show where the money should go. Here are different types of endorsements:

1. Blank endorsements have just your signature on the back. Anyone can cash or deposit a check with this endorsement.

2. Restrictive endorsements have "For Deposit Only" on the first line, then your signature below that. This type of check can only be deposited, not to be cashed for money.

3. Special endorsements are for giving your check to another person. This check can only be deposited or cashed by the person designated on the back. For this endorsement, you would write "Pay to the order of" and then the person's name you want to give the check to. You would then sign your name underneath that. 

As seen in your question, Isis Love is signing it as a special endorsement<em />. She is giving her check to Mike Lopez so his name follows "Pay to the order of". The numbers at the bottom would represent the bank account number. 
7 0
3 years ago
A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th
Temka [501]
The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down  "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;upstream&100&b-c&5\\&#10;downstream&100&b+c&2&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;100=(b-c)5\\&#10;\qquad \frac{100}{5}=b-c\\&#10;\qquad 20=b-c\\&#10;\qquad 20+c=\boxed{b}\\&#10;100=(b+c)2\\&#10;\qquad 50=b+c\\&#10;\qquad 50=\boxed{20+c}+c&#10;\end{cases}

solve for "c", to see what's the current's speed

what's "b"?  well 20+c = b
4 0
3 years ago
A company developing a new cellular phone plan intends to market their new phone to customers who use text and social media ofte
Ber [7]

Answer:

A customer who sends 78 messages per day would be at 99.38th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average of 48 texts per day with a standard deviation of 12.

This means that \mu = 48, \sigma = 12

a. A customer who sends 78 messages per day would correspond to what percentile?

The percentile is the p-value of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 48}{12}

Z = 2.5

Z = 2.5 has a p-value of 0.9938.

0.9938*100% = 99.38%.

A customer who sends 78 messages per day would be at 99.38th percentile.

8 0
3 years ago
Helpp me plz respond
spayn [35]
The ratio is 1:6 for this
6 0
3 years ago
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