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tekilochka [14]

3 years ago

8

La profesora reparte 85 cromos entre tres alumnos. Al Juan le da el doble de cromos que a Pedro y a María le da 9 cromos más que

a Pedro. ¿Cuántos cromos tiene cada uno?

1 answer:

NeX [460]3 years ago

5 0

Answer:

can u please translate to english plz

Step-by-step explanation:

bruh

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The diagram below shows an Isosceles triangle. Label the base angles and the vertex

Dmitry [639]

The base angles of an isosceles triangle are equal

The base angles are 15 degrees, while the vertex angle is 150 degrees

The base angles are given as:

Base = (6a- 3) and (a + 12)

So, we have:

$\mathbf{6a -3 =a + 12}$

Collect like terms

$\mathbf{6a -a =3 + 12}$

$\mathbf{5a = 15}$

Divide both sides by 5

$\mathbf{a = 3}$

Substitute 3 for a in Base = (6a- 3),

$\mathbf{Base = 6 \times 3 - 3}$

$\mathbf{Base = 18 - 3}\\$

$\mathbf{Base = 15}$

So, the base angle is 15 degrees.

The vertex angle is calculated using:

$\mathbf{Vertex=180 -2 \times Base}$

So, we have:

$\mathbf{Vertex=180 -2 \times 15}$

$\mathbf{Vertex=150 }$

Hence, the vertex angle is 150 degrees

Read more about isosceles triangles at:

brainly.com/question/25739654

6 0

2 years ago

125 a la octava potencia? <br>please lo necesito

telo118 [61]

No se si esté correcto, buena suerte!:)

8 0

3 years ago

What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?

ANTONII [103]

The slope would be 1/4 because to find the perpendicular slope, you find the negative reciprocal

3 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago

Which of the following expressions could be used to estimate the difference between -12.34 and -4.8?

Sveta_85 [38]

-12+5

for -12.34,we take it as -12
for -4.8,we take it as -5

to measure the difference,here's what you need to do

-12-(-5)
=-12+5
thus the ans is -12+5

hope it helps

6 0

3 years ago

Read 2 more answers