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3 years ago

Find the interest rate r given I=$ 56,P=450 and t = 6 years , round your answer to the nearest

Mathematics

1 answer:

m_a_m_a [10]3 years ago

5 0

Answer:

0.163

Step-by-step explanation:

P = I (1 + r)ᵗ

450 = 56 (1 + r)⁶

8.036 = (1 + r)⁶

log₆ 8.036 = 1 + r

log 8.036 / log 6 = 1 + r

1.163 = 1 + r

r = 0.163

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Choose the correct graph to fit the inequality<br><br> y<16x ^2

Luda [366]

Answer:

The solution in the attached figure

Step-by-step explanation:

we have

$y$

we know that

The solution of the inequality is the shaded area below the dashed line of the parabola

The equation of the dashed line is the vertical parabola $y=16x^{2}$

therefore

The solution in the attached figure

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3 years ago

Enter all answers to the nearest tenth.

rodikova [14]

Answer:

What is the probability the mean of his sample will be between $70.00 and $80.00? = 64/64 =1

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4 0

3 years ago

I can't work out what k is?

monitta

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3 years ago

What is n?<br> No links!! I repeat NO links

rewona [7]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

A small town has 2000 inhabitants. At 8 AM, 160 people have heard a rumor. By noon half the town has heard it. At what time will

QveST [7]

Answer:

3:36 PM

Step-by-step explanation:

Let fraction (y) of the people that heard the rumor , the differential equation that is satisfied by the by y is,

$\frac{dy}{dt} = ky(1-y)$

Solving the differential equation,

$y(t) = \frac{y_{o}}{[y_{o} + (1 + y_{o})e^{-kt}]}$

The total number of inhabitants of the town = 2000

The number of people that heard the rumor = 160

At 8 AM, let t = 0,

$y(0) = \frac{160}{2000}$

= 0.08

By noon, half of the town as heard the rumor.

Then,

$y(4) = \frac{1}{2}$

Therefore,

$\frac{1}{2} = \frac{0.08}{[0.08 + (1 - 0.08)e^{-4k}]}$

$\frac{0.08}{[0.08 + 0.92e^{-4k}]} = \frac{1}{2}$

$0.08 + 0.92e^{-4k} = 0.16$

$0.92e^{-4k} = 0.16 - 0.08$

$0.92e^{-4k} = 0.08$

$e^{-4k} = \frac {0.08}{0.92}$

$k = - \frac{1}{4} In(\frac {0.08}{0.92})$

k ≈ 0.06106

Calculating time, t when y(t) = 90%

⇒ y(t) = 0.9

$\frac{0.08}{[0.08 + 0.92e^{-0.06106t}]} =0.9$

$0.08 + 0.92e^{-0.06106t} = \frac {0.9}{0.08}$

$0.08 + 0.92e^{-0.06106t} = 0.089$

$0.92e^{-0.06106t} = 0.089 - 0.08$

$0.92e^{-0.06106t} = 0.0089$

$t = - \frac{1}{0.06106}In (\frac{0.0089}{0.92})$

t = 7.59 hours

⇒ 7 hours 36 minutes

From 8 A.M. plus 7 hours 36 minutes = 3:36 PM

At 3:36 PM will 90% of the population have heard the rumor

7 0

3 years ago