1st quartile: 11
median: 38.50000
3rd quartile: 45
<h3>According to the given information:</h3>
- Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
- There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
- 6,7,15,36, or the left-most half of the data, make up the sample.
- The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
- 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
- The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
- The biggest value deviates 10.5 from the median (49-38.5)
Measure descriptive statistics
1st quartile: 11
median: 38.50000
3rd quartile: 45
To know more about quartile visit:
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I understand that the question you are looking for is :
2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45
Answer:
-4 3/4, -4 1/2, -4 1/4
Step-by-step explanation:
Answer:
The value of AB is ![\left[\begin{array}{ccc}21\\11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%5C%5C11%5Cend%7Barray%7D%5Cright%5D)
and it's not possible to multiply BA.
Step-by-step explanation:
Consider the provided matrices.
![A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D)
, ![B=\left[\begin{array}{ccc}3\\5\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.
Multiply AB
Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:
![AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
![AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5Ctimes%203%2B3%5Ctimes%205%5C%5C2%5Ctimes%203%2B1%5Ctimes%205%5Cend%7Barray%7D%5Cright%5D)
![AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%2B15%5C%5C6%2B5%5Cend%7Barray%7D%5Cright%5D)
![AB=\left[\begin{array}{ccc}21\\11\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%5C%5C11%5Cend%7Barray%7D%5Cright%5D)
Hence, the value of AB is
Now calculate the value of BA as shown:
Multiply BA
Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.
We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.
That means number of column of first matrix should be equal to the number of rows of second matrix.
Hence, it's not possible to multiply BA.
x is equal to - 2/3 after collecting like terms
