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leva [86]
3 years ago
14

How many 7 digit phone numbers are there assuming the first digit can't be a 0 or a 1?

Mathematics
1 answer:
Anettt [7]3 years ago
7 0
The first digit can be any one of the numbers 2-9 That a total of 8 numbers.

The next 6 digits can be any permutation of 6  from the numbers  0 to 9.
(10 numbers)

nPr  =  n! / r!

so here we have  10P6  = 10! / 6!  =  10*9*8*7  =  5040

So final answer  is 8 * 5040 = 40,320
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Answer:

y maximum is at 1 for both the points (4,1) and (-4,1)

Step-by-step explanation:

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The doctor prescribed Mrs.Larson 5 milliliters of medicine each day for 3 days.How many milliliters of medicine will she take al
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3 years ago
Read 2 more answers
1)
iragen [17]
Part 1) we know that
Volume of rectangular prism=L*W*H-------> 3*6*4-----> 72 units ³
and 
Volume of rectangular prism=Area of the base*H
Area of the base B=L*W------> 3*6----> 18 units²
so
Volume of rectangular prism=18*4-----> 72 units³

the answer Part 1) is the option
 C) V=Bh

Part 2) we know that
Volume of rectangular prism=L*W*H-------> 5*2*3-----> 30 units ³
and 
Volume of rectangular prism=Area of the base*H
Area of the base B=L*W------> 5*2----> 10 units²
so
Volume of rectangular prism=10*3-----> 30 units³

the answer Part 2) is the option
 <span>C) V=Bh

Part 3) </span>we know that
Volume of rectangular prism=B*H
B=area of the base--------> 5*3-----> 15 units ²
H=3 units
Volume of rectangular prism=15*3-----> 45 units³
and 
Volume of rectangular prism=L*W*H
Volume of rectangular prism=5*3*3-----> 45 units³

the answer Part 3) is the option
<span>C) V=LWH 

Part 4) </span>Part 3) we know that
Volume of rectangular prism=B*H
B=area of the base--------> 5*5-----> 25 units ²
H=7 units
Volume of rectangular prism=25*7-----> 175 units³
and 
Volume of rectangular prism=L*W*H
Volume of rectangular prism=5*5*7-----> 175 units³

the answer Part 4) is the option
C) V=LWH 
3 0
3 years ago
The angle a is acute and sec a
Anna007 [38]

Fundamentally you can get there using the identity

... sin(a)² + cos(a)² = 1

... 1/cosec(a)² + 1/k² = 1 . . . . . substituting for sec(a) and sin(a)

... 1/cosec(a)² = 1 - 1/k² = (k² -1)/k² . . . . subtract 1/k²

... cosec(a)² = k²/(k² -1) . . . . . Multiply by cosec(a)²k²/(k²-1)

... cosec(a) = k/√(k²-1) . . . . . .take the square root

_____

You can get there slightly faster using the identities tan²=sec²-1; csc=sec/tan.

7 0
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