Answer:
200
Step-by-step explanation:
The simplified form of this equation is 5^3.
You simplify these types of equations by adding/subtracting the exponents, since there is multiplication/division and the constant is the same throughout.
Answer:
Degree = 1
Step-by-step explanation:
Given:
The differential equation is given as:

The given differential equation is of the order 2 as the derivative is done 2 times as evident from the first term of the differential equation.
The degree of a differential equation is the exponent of the term which is the order of the differential equation. The terms which represents the differential equation must satisfy the following points:
- They must be free from fractional terms.
- Shouldn't have derivatives in any fraction.
- The highest order term shouldn't be exponential, logarithmic or trigonometric function.
The above differential equation doesn't involve any of the above conditions. The exponent to which the first term is raised is 1.
Therefore, the degree of the given differential equation is 1.
The ball will bounce 72 cm high if dropped from a height of 120 cm
<u>Solution:</u>
Given, The height that a ball bounces varies directly with the height from which it is dropped.
A certain ball bounces 30 cm when dropped from a height of 50 cm.
We have to find how high will the ball bounce if dropped from a height of 120 cm?
Now, according to given information,
When dropped from 50 cm ⇒ bounces 30 cm
Then, when dropped from 120 cm ⇒ bounces "n" cm
Now by Chris cross method, we get,

Hence, the ball bounces 72 cm high.
24+40=64..
GFC 24&20=8
64/8=8
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