When you draw this out, what you have is a right triangle problem. The height of the rope from the ground is 12 (a side), the distance she is from the base of the tree is 5 (a side), and the length of the rope is the hypotenuse. Use Pythagorean's Theorem to find the length of the hypotenuse: 5^2+12^2 = c^2 or
25+144 = c^2 and c^2 = 169, which makes the length of the rope come out to be 13 feet long.

8 0

4 years ago

The function a(t)=t^(1/2)−t^(−1/2) m/s^2 represents the acceleration of a particle moving along a horizontal axis. At time t=0,

garri49 [273]

Answer:

see below

Step-by-step explanation:

a(t)=t^(1/2)−t^(−1/2)

We integrate to find the velocity

v(t) = integral t^(1/2)−t^(−1/2) dt

= t ^ (1/2 +1) t ^ (-1/2 +1)

------------ - ----------------- + c where c is the constant of integration

3/2 1/2

v(t) = 2/3 t^ 3/2 - 2 t^ 1/2 +c

We find c by letting t=0 since we know the velocity is 4/3 when t=0

v(0) = 2/3 0^ 3/2 - 2 0^ 1/2 +c = 4/3

0+c =4/3

c = 4/3

v(t) = 2/3 t^ 3/2 - 2 t^ 1/2 +4/3

To find the position function we need to integrate the velocity

p(t) = integral 2/3 t^ 3/2 - 2 t^ 1/2 +4/3 dt

2/3 t ^ (3/2 +1) 2 t ^ (1/2 +1) 4/3t

------------ - ----------------- + ------------- + c

5/2 3/2 1

p(t) = 4/15 t^ 5/2 - 4/3t ^ 3/2 + 4/3t +c

We find c by letting t=0 since we know the position is -4/15 when t=0

p(0) = 4/15 0^ 5/2 - 4/3 0 ^ 3/2 + 4/3*0 +c = -4/15

0 +c = -4/15

c = -4/15

p(t) = 4/15 t^ 5/2 - 4/3t ^ 3/2 + 4/3t -4/15

8 0

3 years ago

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In a competition between players X and Y, the first player to win three games in a row or a total of four games wins. How many w

OLEGan [10]

Answer:

The competition can be played in 7 different ways

Step-by-step explanation:

First game : X

Second game : Y

Third game : Y

After that either X or Y can win

<h3>¹Case - 1: Y wins the fourth game:</h3>

The competition ends with Y winning as he/she won 3 games in a row

<h3>Case - 2: X wins the fourth game:</h3>

more games are required to decide the winner

<h3>Sub-case - a: X wins the fifth game:</h3>

more games are required to decide the winner

<h3>²Sub-sub-case - i: X wins the sixth game:</h3>

The competition ends with X winning as he/she won 3 games in a row

<h3>³⁻⁴Sub-sub-case - ii: Y wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

<h3>Sub-case - b: Y wins the fifth game:</h3>

more games are required to decide the winner

<h3>⁵Sub-sub-case - i: Y wins the sixth game:</h3>

The competition ends with Y winning as he/she won 4 games in total

<h3>⁶⁻⁷Sub-sub-case - ii: X wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

∴<u>The competition can be played in 7 different ways</u>

7 0

4 years ago

When 31 times a number is increased by 40, the answer is the same as when 200 is decreased by the number

mojhsa [17]

$31x+40=200-x\\32x=160\\x=160/32\\x=5$

The number is 5.

3 0

4 years ago

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