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ArbitrLikvidat [17]
3 years ago
6

Question 20 points if correct

Mathematics
2 answers:
True [87]3 years ago
7 0
Is This On Khan Academy because I be needing help
Vlada [557]3 years ago
5 0

Answer:

B = 155° , C = 25° , D = 155°

Step-by-step explanation:

Given

A = 25°

C = A = 25° [ Vertically Opposite angles ]

Now

A + B = 180°( being linear pair)

25° + B = 180°

B = 180° - 25°

B = 155°

Also

D = B = 155°( vertically opposite angles )

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The collection of all input values is the ___ of the function ?
hichkok12 [17]

Answer:

Domain

Step-by-step explanation:

Input Values Form the Domain of the Function

Mathematicians call the set of all input values for a function its domain.

3 0
2 years ago
If your purchases of shoes increase from 9 pairs per year to 11 pairs per year when your income increases from $19,000 to $21,00
Leni [432]

Answer: commom resources good

Step-by-step explanation:

The question above signifies that I can't eliminate shoes from my list. To me, shoes are inexcludable. You can see that as my income increases, my purchases of shoes increase.

I chose common resources good because they are non-excludable (something difficult to eliminate), but can compete with other goods. This means that their availability to other people decreases when they are being used up.

Other types of goods besides common resources good are

- Private goods (products that are easily eliminated and rival)

-Club goods (excludable products but non rival)

-Public goods (unable to eliminate and non-rival)

8 0
3 years ago
What is an equation of the line that passes through the points (4, -4) and<br> (-4,-4)?
aalyn [17]

Answer:

y=-4

Step-by-step explanation:

i think its right

4 0
3 years ago
A business was valued at £80000 at the start of 2013. In 5 years the value of this business raised to £95000. this is equivalent
Yuri [45]

the yearly increase of x% assumes is compounding yearly, so let's use that.

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\£95000\\ P=\textit{original amount deposited}\dotfill &\£80000\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases}

95000=80000\left(1+\frac{~~ \frac{r}{100}~~}{1}\right)^{1\cdot 5}\implies \cfrac{95000}{80000}=\left( 1+\cfrac{r}{100} \right)^5 \\\\\\ \cfrac{19}{16}=\left( 1+\cfrac{r}{100} \right)^5\implies \sqrt[5]{\cfrac{19}{16}}=1+\cfrac{r}{100}\implies \sqrt[5]{\cfrac{19}{16}}=\cfrac{100+r}{100} \\\\\\ 100\sqrt[5]{\cfrac{19}{16}}=100+r\implies 100\sqrt[5]{\cfrac{19}{16}}-100=r\implies 3.5\approx r

4 0
2 years ago
Solve this polynomial:
nadezda [96]

Answer:

  4ab +10b

Step-by-step explanation:

Perhaps you want to simplify the expression.

  (2.5ab+14b)-(-1.5ab+4b)=2.5ab+14b+1.5ab-4b\\\\=ab(2.5+1.5)+b(14-4)=\boxed{4ab+10b}

8 0
2 years ago
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