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Inga [223]
3 years ago
12

How many ounces are in a cup

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
5 0
8 ounces are in a cup
AlekseyPX3 years ago
5 0
8 fluid ounces in one cup
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A population, P(t) (in millions) in year t, increases exponentially. Suppose P(9)=16 and P(18)=24. a) Find a formula for the pop
jenyasd209 [6]

Answer:\frac{32}{3}\left ( 1.0460\right )^t

Step-by-step explanation:

Given

Population changes exponentially

P\left ( t\right )=ab^t

P\left ( 9\right )=16------1

P\left ( 9\right )=16=ab^8

P\left ( 18\right =24=ab^{18}-----2

divide 1 & 2 we get

\frac{24}{16}=\frac{b^{18}}{b^9}

\frac{3}{2}=b^9

Substitute b^9 in 1 we get

a=\frac{32}{3}

Thus P\left ( t\right )=\frac{32}{3}\left ( 1.0460\right )^t

8 0
3 years ago
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Plane A leaves the Calgary airport at a bearing of 70 degrees and travels a distance of 420km. Plane B leaves the Calgary airpor
HACTEHA [7]

Answer:

16650 km

Step-by-step explanation:

If plane A leaves from Calgary airport at a nearing of 70 degree, it would end up on the first quadrant. Since we are not given exact bearing here we would assume both planes begin from the first quadrant, they move from North. Example plane A moves North 70 degrees.

Plane B will move North 280 degrees and end up in the fourth quadrant (because each quadrant is 90 degrees so we would have 90+90+90+10=280)

Distance apart = 70+80=150 degrees( since all four quadrants =360 degrees)

1 degree= 111km (approximate metric equivalent of degrees)

Therefore distance apart = 150 degrees ×111km = 16650km

5 0
3 years ago
Solve using the standard algorithm 232 * 4 =
miskamm [114]
It's = to 928 you just have to multiply 232 * 4
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HOPE THIS HELPS
6 0
3 years ago
Estimate the square root of 27 over 4 to the nearest 10th
mars1129 [50]

Answer:

1.3

Step-by-step explanation:

7 0
4 years ago
Solve the quadratic equation by using the quadratic formula. if the solution are not real, enter N/A 3x^2-7x+1=0
Vsevolod [243]

Answer:

\displaystyle x=\frac{7\pm\sqrt{37}}{6}

Step-by-step explanation:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-7)\pm\sqrt{(-7)^2-4(3)(1)}}{2(3)}\\\\x=\frac{7\pm\sqrt{49-12}}{6}\\ \\x=\frac{7\pm\sqrt{37}}{6}

7 0
2 years ago
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