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Mars2501 [29]
3 years ago
9

Solve. x² + 6x + 9 = 12 (Choices in photo)

Mathematics
2 answers:
Irina18 [472]3 years ago
6 0
X^2 + 6x + 9 = 12

X^2 + 6x - 3 = 0

(-6 ± <span>√(6^2 - 4*1*-3) ) / 2

3 </span>± √(48) / 2<span>

</span>3 ± 4√(3) / 2

3 ± 2√(3)
jeyben [28]3 years ago
6 0
To solve this problem and to calculate the value of the variable "x", you must apply the following proccedure:

 1. You have the quadratic equation:
<span>
 x²+6x+9=12

 2. Then:

 </span>x²+6x+9-12=0
 x²+6x-3=0
<span>
 3. You must apply the quadratic formula, which is:

 (-b±√(b^2-4ac))/2a

 a=1
 b=6
 c=-3

 4. Then, the result is:

 x=-3</span>±2√3
<span>
 Therefore, the correct option is the first one: </span>x=-3±2√3
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I do not know how to draw this in full scale​
dezoksy [38]

Answer:

  use the actual dimensions on your drawing

Step-by-step explanation:

"Full scale" simply means you use the actual object dimensions on your drawing of it.

If you don't know the meaning of "plan view", "front elevation", or "side elevation," you may need to consult your curriculum materials or any of numerous references on mechanical drawing.

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If you draw, on paper, patterns for cutting out the pieces that make up the object, you will be well on your way to making the required drawings. For example, the face ABCPEF would represent the front elevation. (The only thing added on the drawing of it is a dashed line representing hidden line RQ 1 cm below line AB.)

The side elevation is the shape of AQHGF on top of the shape EMLD. On your drawing of it, the line for EM is the same line as the line representing FG.

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5 0
3 years ago
Lucy spent a total of $6.60 on 5 apples and a package of grapes. If the package of grapes cost $2.35, how much did each apple co
erastova [34]

Answer:

<h2>0.85</h2>

Step-by-step explanation:

apple cost = total cost - grapes package cost

5 apples cost = 6.60 - 2.35

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= 0.85

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4 0
3 years ago
Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10
damaskus [11]

Answer:

4

Step-by-step explanation:

set

f(x,y)=x+y\\

constrain:

g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10

Partial derivatives:

f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2

Lagrange multiplier:

grad(f)=a*grad(g)+b*grad(h)\\

\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]

4 equations:

1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10

By solving:

a=4/9\\b=-2/27\\x+y=4

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4

The maximum is 4

6 0
3 years ago
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