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maxonik [38]
3 years ago
5

(8/v-7)=-5 solve for v

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0
8/v-7=-5  add 7 to both sides

8/v=2  multiply both sides by v

8=2v  divide both sides by 2

4=v

v=4


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What is the area of the triangle?<br> 16<br> 10<br> "T<br> 8
Alexxandr [17]

Answer:

40 unit^2.

Step-by-step explanation:

Area = 1/2 * base * altitude

= 1/2 * 8 * 10

= 40 unit^2.

6 0
2 years ago
Air has a density of 0.001226 g/mL. What volume of air would have a mass of 1.0 lb? A. 2.7 mL B. 815.6 mL C. 37 mL D. 3.7 × 102
Andre45 [30]

Answer:

Volume = 3.7\ * 10^2\ L

Step-by-step explanation:

Given

Density = 0.001226 g/mL

Mass = 1.0\ lb

Required

Determine the volume of air

Density is calculated using:

Density = \frac{Mass}{Volume}

Substitute values for Density and Mass

0.001226 g/mL = \frac{1.0\ lb}{Volume}

Convert lb to grams

0.001226 g/mL = \frac{1.0 * 453.592\ g}{Volume}

0.001226 g/mL = \frac{453.592\ g}{Volume}

Solve for Volume

Volume = \frac{453.592\ g}{0.001226 g/mL}

Volume = 369977.161501\ mL

Convert mL to L

Volume = 369977.161501\ L * 0.001

Volume = 369.977161501\ L

Represent using scientific notation

Volume = 3.69977161501\ * 10^2\ L

Approximate

Volume = 3.7\ * 10^2\ L

8 0
3 years ago
Help please<br>Mark as brainliest
34kurt
You need to use this formula:
([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3)
Now its just getting 'a' by itself.
([c] times [sinA])/([sinC])=[a]
[c]=16 square root of 3
sinA=sin(60)=(square root of 3)/2
sinC=sin(90)=1

Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides.
The final y is:
8 square root of 3
Final answer is C.
8 0
3 years ago
PLZ HELP ASAP RIGHT TRIANGLES
borishaifa [10]
The correct answer is: AB = 3.11

Explanation:
Since

cos(\theta) =  \frac{base}{hypotenuse} --- (1)
\theta = 50°
base = 2

And hypotenuse = AB

Plug in the values in (1):
(1) => cos(50°) = 2/AB

=> AB = 2/0.643
=> AB = 3.11
6 0
3 years ago
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jonny [76]

Why....

________________

4 0
3 years ago
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