All categories

3 years ago

Using the following image, solve for x

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

x = - 6

Step-by-step explanation:

We know that the distance between J and H is 15. So:

$(x + 14) + (x + 13) = 15 \\ x + 14 + x + 13 = 15 \\ 2x = 15 - 14 - 13 \\ 2x = - 12 \\ x = - \frac{ 12}{2} \\ x = - 6$

You might be interested in

What is the value of (-3) (-9) +4 (-5)

katrin2010 [14]

Answer:

Step-by-step explanation:

(-3)(-9)+4(-5)=27+(-20)=27-20=7

7 0

3 years ago

Container is 5 meters wide ,6meters long and 3 meters in depth what is the capacity in quarts

andrezito [222]

In order to determine volume you should multiple w*d*h. So in this case 5*6*3 or 90 cubic meters.

3 0

4 years ago

Jim saw that other bank offered the same rates but compounded the interest more often. Consider if he still put $15,000 into a s

Kazeer [188]

Compound interest is the addition of interest on the interest of the principal amount.

<h3>What is compound interest?</h3>

Compound interest is the addition of interest on the interest of the principal amount. It is given by the formula,

$A = P(1+ \dfrac{r}{n})^{nt}$

As it is given that the principal amount is $15,000; while the rate of interest is 2.8%, and the amount is invested for a period of 5 years.

A.) When the interest is charged weekly,

As we know that there are 52 weeks in a year, therefore, n = 52, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{52})^{52 \times 5}\\\\A = \$17,253.46$

B.) When the interest is charged daily,

As we know that there are 365 days in a year, therefore, n = 365, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{365})^{365 \times 5}\\\\A = \$19,554.55$

C.) When the interest is charged Continuously,

As we know that the formula for continuous compounding is given as,

$A = Pe^{rt}$

Substitute the values, we will get,

$A = 15000 \times (e^{0.024 \times 5})\\\\A= \$16,912.45$

D.) When the interest is charged Monthly,

As we know that there are 12 months in a year, therefore, n = 12, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{12})^{12\times 5}\\\\A = \$15211.23$

E.) When the interest is charged Semi-annually,

As we know that the interest is charged Semi-annually, therefore, n = 2, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{2})^{2\times 5}\\\\A = \$17,237.36$

F.) When the interest is charged Quarterly,

As we know that the interest is charged Quarterly, therefore, n = 4, substitute the values,

$A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{4})^{4\times 5}\\\\A = \$17,245.7$

Learn more about Compound Interest:

brainly.com/question/25857212

4 0

3 years ago

Read 2 more answers

Very large and very small numbers are easier to write in scientific notation. For example, the number, 2360000 would be written

Vedmedyk [2.9K]

1.23e-4 is the same as 1.23 * 10^-4

So, 2.36e6 would be your answer

7 0

3 years ago

What is the lowest value of the range of the function shown on the graph?

kari74 [83]

-2 bc even tho there is a zero-2 will always be the lowest

4 0

3 years ago

Using the following image, solve for x​

Using the following image, solve for x