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olga55 [171]
2 years ago
11

Plot the point (4, −3). Start at the origin. Move 4 units . Move 3 units . The point is at .

Mathematics
2 answers:
Naily [24]2 years ago
7 0

Answer:

the point is D

Step-by-step explanation:

brainliest plz

Allushta [10]2 years ago
5 0
Move 4 units LEFT. Move 3 units DOWN. The point is D.
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The answer is 1/1073741824 or about 9.313 * 10^-10

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Please someone help me to prove this. ​
dem82 [27]
<h3><u>Answer</u> :</h3>

We know that,

\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}

\dag\bf\:sin2A=2sinA\:cosA

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>Now, Let's solve</u> !

\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}

\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}

\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}

\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}

\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}

\leadsto\:\bf{tan(A+B)}

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3 years ago
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4 0
3 years ago
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Eva8 [605]

Answer:

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g ( f(x)) means that you are going to replace x in g(x) for f(x)

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So you have to solve g(x) when x = x+1

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irga5000 [103]

Answer:

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3 years ago
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