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3 years ago

The vertices of a triangle are listed below. Q(-5,2), R(3,2),S(-8,-3) Which of the following classifies the triangle.

Mathematics

1 answer:

Taya2010 [7]3 years ago

3 0

Points Q and R are on a horizontal line (y=2), and point S is off to the left of both of those. The triangle is ...

... B. The tirangle is an obtuse scalene triangle.

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What decimal is equivalent to 3%?

cupoosta [38]

The answer is d, have a good day

6 0

3 years ago

Read 2 more answers

Not drawn

Aleks04 [339]

We see that they are made up of identical squares, meaning that each side of each square is the same length. There are 12 square sides that make up the perimeter of A, so we can do 72/12 which is 6. We see there are ten total square lengths on the perimeter of b, so we can do 6 times 10 which is 60 cm. That’s your perimeter.

7 0

3 years ago

Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The m

DaniilM [7]

Answer:

The trestle meets ground level at 0.875 units and 9.125 units

Step-by-step explanation:

Poorly formatted question.

The given equation is:

$y = -x^2 + 10x - 8$

Required

The point where the trestle gets to the ground level

To do this, we set $y = 0$

So, we have:

$-x^2 + 10x - 8 = 0$

Multiply through by -1

$x^2 -10x + 8 = 0$

Solve using quadratic formula:

$x= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where:

$a = 1; b =-10; c = 8$

So, we have:

$x= \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*8}}{2*1}$

$x= \frac{-(-10) \± \sqrt{68}}{2*1}$

$x= \frac{-(-10) \± 8.25}{2}$

$x= \frac{10 \± 8.25}{2}$

Solve the fraction

$x= 5 \± 4.125$

Split

$x= 5 + 4.125\ or\ x= 5 - 4.125$

$x= 9.125\ or\ x= 0.875$

7 0

3 years ago

On a number line, A is at -2 and B is at 4.

OleMash [197]

It would be at 2. Here is why: -2 and 4 are 6 places away from each other. Now divide that by 3 (for the thirds). so each third is 2. Now thirds 2will be four, so add that to -2 and you get 2.

3 0

3 years ago

A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one

d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

$P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855$

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0

3 years ago