The new area of the given replica's base is; 6250 m²
<h3>What is the required area?</h3>
We are given;
Area of base of statue = 625 m²
Now, an artist wants to create a replica of the base of statue but in the ratio 1:10.
This means that the area will increase by a factor of 10 as 1 sq.unit of the old area will represent 10 sq. units in the new one.
Thus, new area = 625 * 10
New area of statue = 6250 m²
Read more about new area at; brainly.com/question/26858128
Answer:
1. LM < PN
2. AD < DC
3. m<CAB < m<CBA
4. m<1 = m<2
Step-by-step explanation:
Recall: an angle measure is relative to the length of the opposite side. That is, the longer the side opposite to an angle, the larger the measure of that angle and vice versa.
1. LM is opposite to <LNM,
PN is opposite to <NLP
m<LNM is less than m<NLP, therefore,
LM < PN
2. AD is opposite to <ABD
DC is opposite to <DBC
m<ABD is less than m<DBC, therefore,
AD < DC
3. m<CAB is opposite to CB
m<CBA is opposite to CA
CB is less than CA, therefore,
m<CAB < m<CBA
4. The side opposite to <1 is congruent to the side opposite to <2.
Therefore,
m<1 = m<2
Answer:
28.56
Step-by-step explanation:
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Answer:
No
Step-by-step explanation:
When we graph the points we can see that (3, 5) makes it not a linear fuction.
See attached.
Answer:
Student can obtain 15 marks by attempting 8 questions.
Step-by-step explanation:
This question is incomplete; complete question is here.
A student taking a test consisting of 10 questions is told that each questions after the first is worth 2 marks more than the preceding question. If the third question of the test is worth 5 marks.What is the maximum score that the student can obtain by attempting 8 questions?
A students when attempts the questions the sequence formed by the scores he gets will be in the form of a, (a + 2), (a + 4), (a + 6)........
Which will be an arithmetic sequence with a common difference = 2
We know explicit formula of an arithmetic sequence is

Where
= First term of the sequence
a = first term
n = number of term
d = common difference
It is given that 3rd term of this sequence is 5.

a = 5 - 4 = 1
Explicit formula for the sequence will be 

Now if the student attempts 8 questions then from the explicit formula


Therefore, student can obtain 15 marks by attempting 8 questions.