2 years ago

PLEASE HELP WILL MARK BRAINLIEST

Mathematics

1 answer:

Colt1911 [192]2 years ago

3 0

Answer:

Let $x$ = Jose's savings

$59-2x$

I hope I helped you friend! If I am correct, please mark me brainiest. Thanks!

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Answer:

Question A)

$=\sqrt{6}x$

Question B)

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Question C)

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Step-by-step explanation:

We are given:

$\sqrt{6x^2}\, \text{ where } x\geq 0$

We can rewrite the expression:

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The square root and square will cancel each other out. Thus:

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We are given:

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Rewrite:

$=\sqrt{9}\cdot \sqrt{a^3}$

Note that the square root of 9 is simply 3. We can also factor the second part:

$=3\cdot \sqrt{a^2\cdot a}$

Rewriting:

$=3\cdot\sqrt{a^2}\cdot\sqrt{a}$

Simplify:

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We are given:

$\sqrt{50b^4}$

Rewrite. Note that 50 = 25(2):

$=\sqrt{25}\cdot \sqrt{2}\cdot \sqrt{b^4}$

Simplify. We can rewrite the factor as:

$=5\cdot \sqrt{2}\cdot \sqrt{(b^2)^2}$

The square and square root will cancel out. Thus:

$=5\sqrt{2}b^2$

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