The distance between their house and the school from the information given will be 777.60 meters.
<h3>How to calculate the distance?</h3>
The distance between their house and the school will be:
= 80 × 81 × 12
= 77760cm
= 777.60 meters.
When Diane takes 16 min to walk to school, the length of her steps will be:
= 77760/(16 × 90)
= 54 cm
Learn more about distance on:
brainly.com/question/17273444
Answer:
d) 303 8/9
Step-by-step explanation:
4th term = ar^3 and 5th = ar^4 where a = first term and r = common ratio.
So ar^4 / ar^3
= r = 45/-15 = -3.
Working back,:
The first term a = ar^3/ r^3
= -15 / (-3)^3
= -15/-27
= 5/9
Sum of n terms = a * (r^n - 1)/(r-1)
= 5/9 * ((-3)^7 - 1 ) / (-3 -1)
= 303 8/9
You can just plug in one of the points to each equation until you get an equality that is true.
I chose to use (-3,2)
1. 5x+3y=1
5(-3)+3(2)=1
(-15)+ 6 = 1
(-9) = 1 <<<(FALSE)
2. x+5y=3
(-3)+5(2)= 3
(-3)+10= 3
7=3 <<<(FALSE)
3. 3x+5y=1
3(-3) + 5(2)= 1
(-9)+10=1
1=1<<<(TRUE)
So, the correct equation is 3x+5y=1.
Make sense?
If we are supposed to assume that QS=TV
4v+3=7v-9
minus 4v both sides
3=3v-9
add 9
12=3v
divide 3
4=v
v=4
sub back
4v+3=QS=TV
4(4)+3=QS=TV
16+3=QS
19=QS=TV
then answer is C
Y= Mx+b
In the equation of a straight line,the slope is the number "m" that is multiplied on the x, and "b<span>" is the </span>y<span>-intercept (that is, the point where the line crosses the vertical </span>y<span>-axis).</span>
