Could you possibly post a more high quality picture so its not blurry thanks!
Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
Answer:
3/2 or 1 and a half
hope it helps.
just sitting here waiting for brainliest........
Answer:
;;6
Step-by-step explanation:
56 5
