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Vesnalui [34]
3 years ago
12

Find the area of each shape by decomposing each shape into rectangle and/or triangle.

Mathematics
1 answer:
avanturin [10]3 years ago
3 0

Remark

You don't have to decompose the second one, and it is better if you don't. Just find the area as you probably did: use the formula for a trapezoid. You have to assume that the 6cm line hits the 2 bases at right angles for each of them, otherwise, you don't know the height. So I'm going to assume that we are in agreement about the second one.

Problem One

The answer for this one has to be broken down and unfortunately, you answer is not right for the total area, although you might get 52 for the triangle. Let's check that out.

<em><u>Triangle</u></em>

Area = 1/2 * b * h

base = 16 cm

h = 10 - 4 = 6

Area = 1/2 * 16 * 6

Area = 48

<em><u>Area of the Rectangle</u></em>

Area = L * W

L = 16

W = 4

Area = L * W

Area = 16 * 4

Area = 64

<em><u>Total Area</u></em>

Area = 64 + 48

Area = 112  of both figures <<<< Answer

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anzhelika [568]
Molly ate 1/4 and then the last one is 1/8
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3 years ago
A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.
AVprozaik [17]

Answer:

X \sim N(61,14)  

Where \mu=61 and \sigma=14

Since the distribution for X is normal then the distribution for the sample mean  is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 61

\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715

So then is appropiate use the normal distribution to find the probabilities for \bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  The letter \phi(b) is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: \phi(b)=P(z

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(61,14)  

Where \mu=61 and \sigma=14

Since the distribution for X is normal then the distribution for the sample mean \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 61

\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715

So then is appropiate use the normal distribution to find the probabilities for \bar X

8 0
3 years ago
What are the two solutions of 2x^2 = -X^2 - 5x - 1?
Sidana [21]

Answer:

Step-by-step explanation:

Let's solve 2x^2 = -X^2 - 5x - 1.  Consolidate all terms on the left side and write 0 on the right side:

3x^2 + 5x + 1 = 0.  This is a quadratic equation.  Let's solve it for x using the quadratic formula:

a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13.  Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.

Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."  

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

6 0
4 years ago
Ken has read 1/3 of his book what fraction of his book is left to read?​
Stells [14]

Answer:

2/3

Step-by-step explanation:

fraction of book already read = 1/3

fraction which represents whole book = 1 = 3/3

fraction of remaining book = fraction of whole book - fraction of book already read

= 1 - 1/3

= 3/3 - 1/3

= (3-1) /3

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8 0
3 years ago
eight ears of corn and a cantaloupe cost $2.37. six ears of corn and 3 cantaloupes cost $3.51. what does a cantaloupe cost?
abruzzese [7]
In the given question, there are two vital information's give. Firstly 8 ears of corn and 1 cantaloupe cost $2.37. On the other hand 6 ears of corn and 3 cantaloupes cost $3.51.
Let us assume the cost of 1 corn = X
Let us assume the cost of 1 cantaloupe = Y
Then
8X + Y = 2.37
Y = 2.37 - 8X
And
6X + 3Y = 3.51
Now we replace the value of Y we found from the first equation
Then
6X + 3(2.37 - 8X) = 3.51
6X - 24X + 7.11 = 3.51
-18X = 3.51 - 7.11
-18X = -3.6
X = 3.6/18
   = 0.20
So $0.20 is the value of 1 corn. Then the value of a cantaloupe
Y = 2.37 - 8X
   = 2.37 - (8 * 0.20)
   = 2.37 - 1.6
   = 0.77
So cost of a cantaloupe is $0.77
3 0
4 years ago
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