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AURORKA [14]
3 years ago
10

You want your friend to go a movie with you tonight. She has $8.00 to spend. The movie cost $6.50, a large box of popcorn is $4.

00 and a large drink is $4.00. At least how much money (m) do you need to take to get into the movie and purchase and share a large popcorn and drink with your friend? Write an inequality showing this situation and solve.
A. m-8 > 2(6.50) + 4.00+4.00


B. m+8 < 2(6.50) + 4.00+4.00


C. m+8 > 2(6.50) + 4.00+4.00


D. m- 8 < 2(6.50) + 4.00+4.00
Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

Step-by-step explanation:

Answer is C : m+8>2(6.50)+4.00+400

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Find (a) PQ to the nearest tenth and (b) the coordinates of the midpoint of PQ.
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What is the volume of a rectangular prism with a length of 1. 4 meters, a width of 0. 5 meter, and a height of 1. 8 meters? 7. 5
mihalych1998 [28]

The volume of the rectangular prism will be  V=1.26m^{3}

<h3>What will be the volume of the rectangular prism ?</h3>

Given that

\rm Lenth \ of \ the \ rectangular \ prism =1.4\ m

\rm width\ of \ prism=0.5\ m

\rm Height \ of \ prism=1.8\ m

\rm Volume \ of \ the \ Rectangular \ Prism= L\times W\times H

V=1.4\times 0.5\times1.8=1.26 \ m^{3}

Thus the volume of the rectangular prism will be  V=1.26m^{3}

To know more about the volume of the rectangular prism follow

brainly.com/question/24284033

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Use factoring to write an expression that is equivalent to 25b^16-64c^2
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We can write this as the difference of squares:
(5b⁸+8c)(5b⁸-8c)

To write as the difference of squares, take the square root of each term first:
√25b¹⁶ = 5b⁸; √64c² = 8c

Now we write this as a sum in one binomial and a difference in the other:
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Solution for dy/dx+xsin 2 y=x^3 cos^2y
vichka [17]
Rearrange the ODE as

\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y=x^3\cos^2y
\sec^2y\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y\sec^2y=x^3

Take u=\tan y, so that \dfrac{\mathrm du}{\mathrm dx}=\sec^2y\dfrac{\mathrm dy}{\mathrm dx}.

Supposing that |y|, we have \tan^{-1}u=y, from which it follows that

\sin2y=2\sin y\cos y=2\dfrac u{\sqrt{u^2+1}}\dfrac1{\sqrt{u^2+1}}=\dfrac{2u}{u^2+1}
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So we can write the ODE as

\dfrac{\mathrm du}{\mathrm dx}+2xu=x^3

which is linear in u. Multiplying both sides by e^{x^2}, we have

e^{x^2}\dfrac{\mathrm du}{\mathrm dx}+2xe^{x^2}u=x^3e^{x^2}
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Integrate both sides with respect to x:

\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx
e^{x^2}u=\displaystyle\int x^3e^{x^2}\,\mathrm dx

Substitute t=x^2, so that \mathrm dt=2x\,\mathrm dx. Then

\displaystyle\int x^3e^{x^2}\,\mathrm dx=\frac12\int 2xx^2e^{x^2}\,\mathrm dx=\frac12\int te^t\,\mathrm dt

Integrate the right hand side by parts using

f=t\implies\mathrm df=\mathrm dt
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You should end up with

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