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3 years ago

HELP ME PLEASE

Computers and Technology

2 answers:

rosijanka [135]3 years ago

8 0

Answer:

Variable, operator, expression, value.

Explanation:

We could use variables, operators, expressions, and values in a mathematical formula, we're going to do an example with every part.

For this example we're going to use a simple sum formula:

First, we have 3 variables:

sum;

sum1;

sum2;

Second, we have 3 operators:

=, + and *

Third, we have our expression and 1 value:

sum = sum1 + (sum2 * 5);

(sum2 * 5) = expression;

5 = value;

We're going to see the result when we print the variable sum.

Contact [7]3 years ago

5 0

Answer:

variable

expression

operator

result

Explanation:

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Answer:

To obtain substantial performance enhancements, we must exploit ILP across multiple basic blocks.

Explanation:

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3 years ago

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erica [24]

1st Method:

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Hope you could understand.

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2 years ago

Suppose you are given a string containing only the characters ( and ). In this problem, you will write a function to determine w

Whitepunk [10]

Answer:

Code is completed below

Explanation:

Source Code in Java:

class Parenthesis

{

boolean hasBalancedParentheses(String eq) //method to check and return if a set of parenthesis is balanced or not

{

int count=0; //to store count of current unclosed opening brackets

for(int i=0;i<eq.length();i++)

{

if(eq.charAt(i)=='(')

count++;

else if(eq.charAt(i)==')')

count--;

if(count<0) //if count falls below zero, there were more closing brackets than opening brackets till this point

return false;

}

if(count>0) //if count is still more than zero, there were less closing brackets than opening brackets

return false;

return true; //if program reaches this point, it has passed all the tests

}

public static void main(String args[])

{

//testing the function

Parenthesis ob=new Parenthesis();

System.out.println(ob.hasBalancedParentheses("()(()())((())())"));

System.out.println(ob.hasBalancedParentheses(")((()())(()))())"));

}

8 0

3 years ago

Which of the following method calls are legal?a. mathMethod(x);b. mathMethod(y);c. mathMethod(x, y);d. mathMethod(x + y);e. math

Roman55 [17]

Answer:

Option a, b, d, f, and j is legal method calls.

Explanation:

In the given question some information is missing, that is the method definition which can be described as follows:

Method definition:

int x =2, y=3; //defining integer variable

int mathMethod (int x) //method definition

{//method body

int z=x+y; //calculate value

return z; //return value

}

In the given question option a, b, d, f, and j is legal, because these options follow the correct syntax, and other option were incorrect which can be defined as follows:

In option c, It is illegal because it accepts only one parameter.
In option e, It is accepts long number, that's why it is illegal.
In option g, It accepts float value, that's why it is illegal.
In option h, It doesn't accepts any parameter.
In option i, It isn't use in method.

7 0

3 years ago

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alexdok [17]

Answer:

true

Explanation:

4 0

3 years ago