Can anyone please help me to solve this question?

Discuss the core technologies and provide examples of where they exist in society. Discuss how the core technologies are part of

Vika [28.1K]

Answer:

Part A

The core technologies are the technologies which make other technologies work or perform their desired tasks

Examples of core technologies and where they exist are;

Thermal technology, which is the technology involving the work production, storage, and transfer using heat energy, exists in our refrigerators, heat engine, and boilers

Electronic technology is the technology that involves the control of the flow of electrons in a circuit through rectification and amplification provided by active devices. Electronic technology can be located in a radio receiver, printed circuit boards (PCB), and mobile phone

Fluid technology is the use of fluid to transmit a force, provide mechanical advantage, and generate power. Fluid technologies can be found in brakes, automatic transmission systems, landing gears, servomechanisms, and pneumatic tools such as syringes

Part B

The core technologies are the subsystems within the larger systems that make the larger systems to work

The thermal technology in a refrigerator makes use of the transfer of heat from a cold region, inside the fridge, to region of higher temperature, by the use of heat exchange and the properties of the coolant when subjected to different amount of compression and expansion

The electronic technologies make it possible to make portable electronic devises such as the mobile phones by the use miniaturized circuit boards that perform several functions and are integrated into a small piece of semiconductor material

Fluid technologies in landing gears provide reliable activation of the undercarriage at all times in almost all conditions such that the landing gears can be activated mechanically without the need for other source of energy

Explanation:

6 0

3 years ago

Initially, later, and finally are examples of what kind of words

Klio2033 [76]

Im pretty sure that the correct answer is Transition words.

3 0

3 years ago

A support technician uses the ping utility on a system that is online, yet no response is received. What should be allowed throu

alexgriva [62]

Answer:

Internet Control Message Protocol (ICMP) Echo Requests

Explanation:

A system that has Windows Firewall or antivirus or other third party antivirus enabled with their configuration setting set to default, ping command from another device will not be able to see if the device with an enabled firewall is alive.

The ping command sends Internet Control Message Protocol (ICMP) Echo Request to a destination device after the destination device will reply with a Reply packet. However, by default, firewalls, such as Windows firewall blocks ICMP Echo Requests from the external network and pinging will work when the firewall is disabled or an exception is created that lets ICMP Echo Requests pass through the firewall.

4 0

3 years ago

Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *

devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

else // check if n is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;

while(i<=(2*n))

{

sum1+= i;

i++;

}

else // check if n is negative

{

int i=n;

while(i<=(2*n))

{

sum1+= i;

i++;

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop 2 * n to n and storing the sum in "sum1" variable. Finally display sum1 variable .

4 0

3 years ago

Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur

sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

for ip in range(octet_start, octet_end):

forth_octet = forth_octet + 1

if forth_octet > 255:

forth_octet = (forth_octet % 255) - 1

third_octet = third_octet + 1

if third_octet > 255:

third_octet = (third_octet % 255) - 1

second_octet = second_octet + 1

if second_octet > 255:

second_octet = (second_octet % 255) - 1

first_octet = first_octet + 1

if first_octet > 255:

print("No more available IP!")

break

print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0

3 years ago