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FrozenT [24]
4 years ago
9

N a certain city the temperature (in degrees fahrenheit) t hours after 9am was approximated by the function t(t)=80+15sin(πt12)

t(t)=80+15sin⁡(πt12) determine the temperature at 9 am. 80 determine the temperature at 3 pm. 95 find the average temperature during the period from 9 am to 9 pm.
Mathematics
1 answer:
Rzqust [24]4 years ago
6 0
What........................
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Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b obtuse. What must be true?​
kotykmax [81]

Answer:

C

Step-by-step explanation:

If the angle opposite b is the obtuse angle then the answer is a² + c² < b² because in an obtuse triangle, the sum of the squares of the shortest sides must be less than the square of the longest side. In this case, the longest side is the one opposite the largest angle, which is b.

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3 years ago
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Find the slope and the y-intercept of the following equation y = - x/3 - 4
BartSMP [9]

Answer:

The slope is -x/3 and the y-intercept is -4.  

Step-by-step explanation:

8 0
4 years ago
Simplify: -m(7m + 3) – 4m2<br>A. 12m+4<br>B. -11m2-3m<br>C. -11m2+6m<br>D.5 m + 4 ​
Mars2501 [29]

Answer:

- m(7m + 3) - 4 {m}^{2}  \\  - 7m^{2}  - 3m - 4 {m}^{2} \\   - 11 {m}^{2}  - 3m

6 0
4 years ago
Can anyone help me with this?
Papessa [141]

Answer:

5n-10 < 6n-8

n - is the variable that's stands for the unspecified number

step 1. ten is less than 5 times a number

step 2. LESS THAN SIGN :)

step 3. six times the number decreased by 8

......................

oh and if you're looking to simplify that problem I believe it would be worked out like this....5n-10<6n-8....subtract 5 from both sides....-10

6 0
3 years ago
CALLING ALL MATH GENIUS!!! Help! Please!
IrinaK [193]

2) 7/8+1/3+1/2=1\frac{17}{24}, so your answer is A

3) 1/9+1/12, it's LCD (lest common denominator) is 36, \frac{1*4}{9*4} + \frac{1*3}{12*3} = \frac{4}{36} + \frac{3}{36} = \frac{4+3}{36} = \frac{7}{36} so your answer is also A

4) 13+\frac{1}{4} +\frac{2}{3} find the Least Common Multiple (LCM) of

4, and 3, which is 12. Now make the denominators the same as the LCD, 13+\frac{1*3}{4*3} +\frac{2*4}{3*4}. Now Simplify; 13+\frac{3}{12} +\frac{8}{12} =13+\frac{3+8}{12} =13\frac{11}{12}, D is your answer.

5) LCD=9, so make the denominators the same as the LCD, \frac{4}{9} - \frac{1*3}{3*3} = \frac{4}{9} - \frac{3}{9} = \frac{4-3}{9} =\frac{1}{9}. Your answer is B.

6) 30-22\frac{5}{6}, (use.the.rule...a\frac{b}{c}=\frac{ac+b}{c}...because.22\frac{5}{6}.is.an.improper.fraction)

30-\frac{22*6+5}{6} =30-\frac{132+5}{6}=30-\frac{137}{6} = make the denominators the same 30*\frac{6}{6} -\frac{137}{6} =\frac{180}{6} -\frac{137}{6} =\frac{43}{6} =7\frac{1}{6}

7) 9\frac{5}{12} is an improper fraction, so you the previous rule I said to use for improper fractions.

\frac{9*12+5}{12} -4\frac{2}{3} =\frac{108+5}{12}-4\frac{2}{3}, also 4\frac{2}{3} is an improper fraction so use the rule again.

\frac{113}{12} -\frac{12+2}{3} =\frac{113}{12} -\frac{14}{3}, LCD=12

Make the denominators the same \frac{113}{12}-\frac{14*4}{3*4}=\frac{113}{12}-\frac{56}{12} =\frac{113-56}{12} =\frac{57}{12}=\frac{19}{4}=4\frac{3}{4}, the answer is D

8) 21\frac{7}{9}, improper fraction

\frac{21+19+7}{19} -6\frac{8}{19} =\frac{399+7}{19} -6\frac{8}{19} = \frac{406}{19} -6\frac{8}{19}

6\frac{8}{19} is an improper faction

\frac{406}{19}-\frac{6*19+8}{19}  =\frac{406}{19} -\frac{114+8}{19} =\frac{406}{19} -\frac{122}{19} =\frac{406-122}{19}=\frac{284}{19}=14\frac{18}{19}, the answer is B.

9) \frac{8}{9} -\frac{6}{9} =\frac{2}{9}, You're trying to see how much farther he ran on Monday compared to Wednesday, so Monday goes first.

10) \frac{3}{4} -\frac{1}{8} =\frac{5}{8}, You're trying to see how much more you need, so you need to subtract 1/8 (what you already have) and 3/4 to see how much you need left.

11) You're tyring to see how much she need all together, so you're looking for the sum, which is 12\frac{3}{8}, so the answer is C.

12) You're seeing how much he grew over the past years, so you'll be looking for the sum (addition) 1\frac{3}{4}+ 2\frac{2}{3} =4\frac{5}{12}

19) In this problen, Claude used some of his ribbon, which in turn decreased the amount he has left, so you are looking for the difference (In this case, what he has now, vs what he originally had.) 5\frac{1}{2} -4\frac{2}{3}= \frac{5}{6}, your answer is C.

20) Find the time it takes in all the routes by subtracting the time you leave to the time you get there, the answer is route four because it is 2 hours and 5 minutes.

Hope this helps, have a BLESSED and wonderful day, as well as a safe one!

-Cutiepatutie ☺❀❤

4 0
3 years ago
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