Area of trapezoid = (1/2) (b1 + b2) h
= (1/2) x (12 + 24) x 6 sqrt 3
= 108 sqrt 3
area of Hexagon = 2 x Area of trapezoid
= 2 x 108 sqrt 3
= 216 sqrt 3
<em>x</em>² - x
<em>x</em> = 4
4² - 4
16 - 4 = 12
Hope this helps!
Answer:
Step-by-step explanation:
You can't answer c. There is not enough information. Other than there are 14 boys that went, you know nothing about how many went.
Girls going = (3/5) * 20 = 12
Girls not going = 20 - 12 = 8
So, we know that a^2 + b^2 = c^2. Right? That is called the Pythagorean Theorem.
In this case. We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b. a & b are just the two legs of the right triangle.
So, if we say that 39 is a, 40 is b, and x is c. We can plug it into the Pythagorean Theorem.
39^2 + 40^2 = x^2
I'll let you take it from there.
Answer:It should be x=1 not sure thought.
Step-by-step explanation:
