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fredd [130]
3 years ago
9

If NTM is congruent to OUM, SP is congruent to SQ, S is the center of the circle, and OM = 18, find NT. Round the answer to the

hundredths place.
Mathematics
1 answer:
Aleks [24]3 years ago
4 0
OM=18, so OQ=QM=18/2=9.
 Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
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Now when we have a and b, let's just replace them in the general equation:
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