Answer (Please vote me Brainliest if this helps!):
The solution is B.
Step-by-step explanation:
Solve with the quadratic formula
![x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{\left(-7\right)^2-4\cdot \:1\cdot \:13}}{2\cdot \:1}](https://tex.z-dn.net/?f=x_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-%5Cleft%28-7%5Cright%29%5Cpm%20%5Csqrt%7B%5Cleft%28-7%5Cright%29%5E2-4%5Ccdot%20%5C%3A1%5Ccdot%20%5C%3A13%7D%7D%7B2%5Ccdot%20%5C%3A1%7D)
Simplify
![x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{3}i}{2\cdot \:1}](https://tex.z-dn.net/?f=x_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-%5Cleft%28-7%5Cright%29%5Cpm%20%5Csqrt%7B3%7Di%7D%7B2%5Ccdot%20%5C%3A1%7D)
Separate the solutions
![x_1=\frac{-\left(-7\right)+\sqrt{3}i}{2\cdot \:1},\:x_2=\frac{-\left(-7\right)-\sqrt{3}i}{2\cdot \:1}](https://tex.z-dn.net/?f=x_1%3D%5Cfrac%7B-%5Cleft%28-7%5Cright%29%2B%5Csqrt%7B3%7Di%7D%7B2%5Ccdot%20%5C%3A1%7D%2C%5C%3Ax_2%3D%5Cfrac%7B-%5Cleft%28-7%5Cright%29-%5Csqrt%7B3%7Di%7D%7B2%5Ccdot%20%5C%3A1%7D)
![\frac{-\left(-7\right)+\sqrt{3}i}{2\cdot \:1}](https://tex.z-dn.net/?f=%5Cfrac%7B-%5Cleft%28-7%5Cright%29%2B%5Csqrt%7B3%7Di%7D%7B2%5Ccdot%20%5C%3A1%7D)
Apply rule - (-a) = a
![\frac{7+\sqrt{3}i}{2\cdot \:1}](https://tex.z-dn.net/?f=%5Cfrac%7B7%2B%5Csqrt%7B3%7Di%7D%7B2%5Ccdot%20%5C%3A1%7D)
Multiply the numbers: 2 · 1 = 2
![\frac{7+\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B7%2B%5Csqrt%7B3%7Di%7D%7B2%7D)
![\frac{-\left(-7\right)-\sqrt{3}i}{2\cdot \:1}](https://tex.z-dn.net/?f=%5Cfrac%7B-%5Cleft%28-7%5Cright%29-%5Csqrt%7B3%7Di%7D%7B2%5Ccdot%20%5C%3A1%7D)
Apply rule - (-a) = a
![\frac{7-\sqrt{3}i}{2\cdot \:1}](https://tex.z-dn.net/?f=%5Cfrac%7B7-%5Csqrt%7B3%7Di%7D%7B2%5Ccdot%20%5C%3A1%7D)
Multiply the numbers: 2 · 1 = 2
![\frac{7-\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B7-%5Csqrt%7B3%7Di%7D%7B2%7D)
The solutions to the quadratic equations are:
, ![\frac{7-\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B7-%5Csqrt%7B3%7Di%7D%7B2%7D)
Answer:
jumbo 23 oz, grande 16 oz
Step-by-step explanation:
Use g for grande and j for jumbo
The first equation: 28g + 33j = 1207
The second equation: 28g + 53j = 1667
Subtract the first from the second
28g + 53j = 1667
- 28g + 33j = 1207
Equal 20j = 460
j = 23
Put 23 in for j in either equation and solve for g:
28g + 33(23) = 1207
28g + 759 = 1207
28g = 448
g = 16
The statements that apply to the ratio of rice and water are:
- The ratio of rice to water is 1 to 2.5
- The ratio of water to rice is 2.5 to 1
<h3>Ratios</h3>
Ratios are used to compare quantities of different measurements
The entries on the table are given as:
<u>Rice Water</u>
2 5
3 7.5
5 12.5
8 20
<h3>The ratios of both quantities</h3>
The ratio (r) of rice and water is then calculated as:
![r = \frac{Water}{Rice}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7BWater%7D%7BRice%7D)
Pick any corresponding table entry.
So, we have:
![r = \frac{5}{2}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B5%7D%7B2%7D)
Divide
![r = 2.5](https://tex.z-dn.net/?f=r%20%3D%202.5)
This means that, the ratio of rice to water is 1 to 2.5, and the ratio of water to rice is 2.5 to 1
Read more about ratios at:
brainly.com/question/1781657
Answer:
![\huge\boxed{\sf x = 1.8}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csf%20x%20%3D%201.8%7D)
Step-by-step explanation:
![\sf 2x-1.5 = 2.1\\\\Add \ 1.5 \ to \ both \ sides\\\\2x = 2.1 + 1.5\\\\2x = 3.6\\\\Divide \ 2 \ to \ both \ sides\\\\x = 3.6 / 2\\\\x = 1.8\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%202x-1.5%20%3D%202.1%5C%5C%5C%5CAdd%20%5C%201.5%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C2x%20%3D%202.1%20%2B%201.5%5C%5C%5C%5C2x%20%3D%203.6%5C%5C%5C%5CDivide%20%5C%202%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5Cx%20%3D%203.6%20%2F%202%5C%5C%5C%5Cx%20%3D%201.8%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
If you subtract 6.51-9.32 that gets you -2.81+h=1.02, then add -2.81 on both side so you eliminate the negative number on the left and the number on the right becomes 3.83 Which is what h equals