All categories

3 years ago

Lin is 7 years younger than Adrian,

Mathematics

1 answer:

jeka943 years ago

5 0

Answer: Age of Lin is 12

Solution:

Let X= age of Maya

(X/2)+4= age of Adrian

((X/2)+4)-7= age of Lin

X+(X/2)+4+((X/2)+4-7)=61

X+.5X+4+.5X+4-7=61

2X+4+4-7=61

2x=61-8+7

2X=60

X=30 age of Maya

19= age of Adrian

Age of Lin is

=((X/2)+4)-7

=15+4-7

=12

To check if this is correct

You might be interested in

Find the geometric mean between 18 and 7. Write your answer in radical form.

solmaris [256]

Answer: Choice A

Work Shown:

$m = \text{geometric mean of x and y}\\\\m = \sqrt{x*y}\\\\m = \sqrt{18*7}\\\\m = \sqrt{9*2*7}\\\\m = \sqrt{9}*\sqrt{2*7}\\\\m = 3\sqrt{14}\\\\$

3 0

2 years ago

The Big Paint “Mix-Up”

sladkih [1.3K]

Answer:

1. 8 quarts of blue

2. 12 quarts of yellow

3. 10 pints of red

4. 24 pints of yellow

5. 16 quarts of light blue

6. 9 quarts of red

3 0

2 years ago

The enrollment at Temple Junior High School has a change of ─ 60 over a 3 year period. What is the average change per year?

GaryK [48]

Answer:

- 20

Step-by-step explanation:

Total Change in enrollment = - 60

Period of time at which change occurred = 3 years

Average change per year :

Total change in enrollment / period at which change occurred

= - 60 / 3

= - 20

Average change of - 20 enrollments per year

4 0

2 years ago

One of two or more Expressions that are multiplied together to get a product

slamgirl [31]

Answer:

factor

Step-by-step explanation:

We assume this is a vocabulary question and you want the word that has the definition you have supplied.

Such an expression is called a <em>factor</em>.

6 0

2 years ago

Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent

Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly among the given student the probability that this student is wearing a ring or necklace is

$P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1$

$P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4$

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

7 0

2 years ago