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Vaselesa [24]
4 years ago
13

If h = 3.7 then what is 0.8 + h?

Mathematics
1 answer:
Gnoma [55]4 years ago
4 0
H=3.7
Then 0.8+h=0.8+3.7
=4.5
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If degree of a polynomial ab³c²​
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Step-by-step explanation:

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3 years ago
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the function f(x)= x1/3 is transformed to get function h. h(x)= (2x)1/3+5 which statements are true about function h
Bess [88]

The transformation of a function may involve any change. The function f(x) is vertically stretched and shifted 5 units upwards to form h(x).

<h3>How does the transformation of a function happen?</h3>

The transformation of a function may involve any change.

Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs) etc.

If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:

Horizontal shift (also called phase shift):

  • Left shift by c units, y=f(x+c) (same output, but c units earlier)
  • Right shift by c units, y=f(x-c)(same output, but c units late)

Vertical shift

  • Up by d units: y = f(x) + d
  • Down by d units: y = f(x) - d

Stretching:

  • Vertical stretch by a factor k: y = k \times f(x)
  • Horizontal stretch by a factor k: y = f(\dfrac{x}{k})

The function f(x)=x^(1/3) is transformed to form the function of  h(x)=(2x)^(1/3)+5. Therefore, the transformation made to the function is,

Vertically stretched by a factor of 2^(1/3) ⇒ 2^(1/3) × x^(1/3) = (2x)^(1/3)

Up by 5 units ⇒ (2x)^(1/3) + 5

Hence, the function f(x) is vertically stretched and shifted 5 units upwards to form h(x).

Learn more about Transforming functions:

brainly.com/question/17006186

#SPJ1

7 0
2 years ago
What is the areaof a circle having a given diameter. d=16 cm
Elan Coil [88]
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If you're looking for the answer in terms of pi, 64pi is the answer.
8 0
4 years ago
Doug entered a canoe race. he rowed 3 1/2 miles in 1/2 hours what is his average speed in miles per hour
lana [24]
3.5miles/.5hours
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7mph



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6 0
3 years ago
Write two expressions with unlike denominators whose sum is x-3/x+2, I need help it is confusing for me.
skad [1K]

Answer:

\displaystyle A=\frac{x-2}{x+3}

\displaystyle B=\frac{-5}{(x+3)(x+2)}

Step-by-step explanation:

We need to find two expressions with unlike denominators what sum

\displaystyle S=\frac{x-3}{x+2}

Let's suppose one of the expressions is:

\displaystyle A=\frac{x-2}{x+3}

Now we subtract S minus A to find the other expression B:

\displaystyle B=S-A=\frac{x-3}{x+2}-\frac{x-2}{x+3}

Multiply the first fraction by x+3 and the second by x+2;

\displaystyle B=(x+3)\frac{x-3}{(x+3)(x+2)}-(x+2)\frac{x-2}{(x+3)(x+2)}

Operating:

\displaystyle B=\frac{x^2-9}{(x+3)(x+2)}-\frac{x^2-4}{(x+3)(x+2)}

Subtracting both fractions with like denominators:

\displaystyle B=\frac{x^2-9-(x^2-4)}{(x+3)(x+2)}

Simplifying:

\displaystyle B=\frac{-5}{(x+3)(x+2)}

Thus the two expressions are:

\displaystyle A=\frac{x-2}{x+3}

And

\displaystyle B=\frac{-5}{(x+3)(x+2)}

8 0
3 years ago
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