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Nesterboy [21]
2 years ago
11

In a particular​ year, a total of 44,064 students studied in two of the most popular host countries when traveling abroad. If 83

82 more students studied in the most popular host country than in the second most popular host​ country, find how many students studied abroad in each country. There were _______ students who studied abroad in the most popular host country.
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
6 0

Answer:

The answer would be 35066 :)

Step-by-step explanation:

(y+5554) + y = 64578

Combine like terms

2y = 64578-5554

2y = 59024

y = 29512

x = 29512 + 5554 = 35066

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A rectangular garden is to be fenced so that one of the sides is 5 feet longer than an adjacent side (s). Which of the following
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The yearbook club had a meeting. The meeting had 24 people, which is three-fourths of the club. How many people are in the club?
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3 years ago
Write an epression that shows how to multiply 7×256 using expanded form and the Distributive Property
posledela

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4 0
3 years ago
If a 10 symbol sequence is sent through the channel,what is the probability that up to 3 symbols are in error out of the 10trans
lina2011 [118]

Answer: 0.171887

Step-by-step explanation:

Given that S0 and S1 are binary symbol of equal probabilty;

P(S0) = P(S1) = 0.5

This probability is a Binomial random variable of sequence Sn, where Sn counting the number of success in a repeated trials.

P(Sn =X) = nCx p^x (1-p)^(n-1)

Pr(at most 3) = P(0<= x <=3) = P(X=0) + 0) + P(X=1) + P(X=2) + P(X=3)

Since there are only 2 values that occur in sequence 0 and 1 ( or S0 and S1).Let the distribution be given by the sequence (0111111111),(1011111111),(11011111111),...(1111111110) for Sn= 1 is the sequence for 1 error.

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= 1 × (0.5)^10 + 10 × (0.5)^10 + 45 × (0.5)^10 + 120 × (0.5)^10

=0.000977 + 0.00977 + 0.04395 + 0.11719

= 0.171887

3 0
3 years ago
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